Python|Python 15 Python15

课上代码

#全局变量(global variable)和局部变量(local variable)和差别 def discounts(price, rate): final_price = price * rate print("这里试图打印全局变量old_price的值：", old_price) return final_priceold_price = float(input("请输入原价：")) rate = float(input('请输入折扣率：')) new_price = discounts(old_price, rate) print('打折后价格是：', new_price)>>> =================== RESTART: C:/Users/xin/Desktop/test.py =================== 请输入原价：100 请输入折扣率：0.8 这里试图打印全局变量old_price的值： 100.0 打折后价格是： 80.0

def discounts(price, rate): final_price = price * rate #print("这里试图打印全局变量old_price的值：", old_price) old_price = 50 print('修改后old_price的值1是：', old_price) return final_priceold_price = float(input("请输入原价：")) rate = float(input('请输入折扣率：')) new_price = discounts(old_price, rate) print('修改后old_price的值2是：',old_price) print('打折后价格是：', new_price)>>> =================== RESTART: C:/Users/xin/Desktop/test.py =================== 请输入原价：100 请输入折扣率：0.8 修改后old_price的值1是： 50 修改后old_price的值2是： 100.0 打折后价格是： 80.0

二. 测试题

目测以下程序会打印什么内容

def fun(var): var = 1314 print(var, end = '')var = 520 fun(var) print(var)

1314520

目测一下程序会打印什么内容

var = ' Hi 'def fun1(): global var var = ' Baby ' return fun2(var)def fun2(var): var += 'I love you' fun3(var) return vardef fun3(var): var = ' Jack 'print(fun1())

Baby I love you

三. 动动手

编写一个函数，判断传入的字符串参数是否为回文联，也就是既可顺读，也可倒读，例如：abcba

#个人代码 #没有编写函数，而且比较复杂，需要把一句话拆成两段再比较是不是相同 checking_string = input("Please input a sentence: ") length = len(checking_string) half_length = length // 2 L1 = [] L2 = []checking_string1 = checking_string[ : (half_length + 1)] checking_string2 = checking_string[half_length : ]length1 = len(checking_string1) length2 = len(checking_string2) for i in range(0, length1): L1.append(checking_string1[i]) for j in range(length2 - 1, -1, -1): L2.append(checking_string2[j])if L1 == L2: print("Yes!") else: print("No!")

#参考代码1 def palindrome(string): length = len(string) last = length - 1 length //= 2 flag = 1 for each in range(length): if string[each] != string[last]: flag = 0 last -= 1if flag == 1: return 1 else: return 0string = input("Please input a sentence: ") if palindrome(string) == 1: print("Yes!") else: print("No!")

#参考代码2 def palindrome(string): list1 = list(string) #这一步想到了，但就是不知道怎么实现 list2 = reversed(list1) if list1 == list(list2): return "Yes!" else: return "No!" print(palindrome('abcba'))

【Python|Python 15】二. 编写一个函数，分别统计处传入字符参数(可能不止一个参数)的英文字母，空格，数字和其他字符的个数

#个人代码 #还是没有写出函数，另外这只能测试一个参数 alphabets = 'QWERTYUIOPLKJHGFDSAZXCVBNMqwertyuioplkjhgfdsazxcvbnm' number = '0123456789' other_character = "~`!@#$%^&*()_+-={}|[]\:; '<>?,./" num_alphabets = 0 num_number = 0 num_other_character = 0 num_space = 0string = input("Please input a sentence: ") for i in string: if i in alphabets: num_alphabets += 1 elif i == ' ': num_space += 1 elif i in number: num_number += 1 elif i in other_character: num_other_character += 1print(num_alphabets, num_number, num_other_character, num_space)

#参考代码 def count(*param): length = len(param) for i in range(length): letters = 0 space = 0 digit = 0 others = 0 for each in param[i]: if each.isalpha(): letters += 1 elif each.isdigit(): digit += 1 elif each == ' ': space += 1 else: others += 1 print('第%d个字符串共有：英文字母%d个，数字%d个，空格%d个，其他字符%d个。' % (i + 1, letters, digit, space, others))count('I love fishc.com.', 'I love you, you love me.')