利用C语言实现五子棋游戏利用C语言实现五子棋游戏

本文实例为大家分享了C语言实现五子棋游戏的具体代码，供大家参考，具体内容如下
一、前言
本文将先介绍五子棋运行所需要的函数，最后串联成完整代码。
我们需要实现的功能有：1.菜单menu函数
2.初始化棋盘Initboard函数
3.显示棋盘Displayboard函数
4.实现人机、人人模式的选择
5.落子函数 playermovecomputermove
6.判断输赢ifwin函数
先来看看运行效果吧！

文章图片

二、头文件

#define _CRT_SECURE_NO_WARNINGS#include #include #include#include#include#define ROW 10//定义棋盘的宽#define COL 10//定义棋盘的长//定义常量方便全局的修改void Initboard(char board[ROW][COL], int row, int col); //初始化棋盘void Displayboard(char board[ROW][COL], int row, int col); //展示棋盘void Playermove_1(char board[ROW][COL], int row, int col,int*px,int *py); //玩家一下棋void Playermove_2(char board[ROW][COL], int row, int col,int*px, int *py); //玩家二下棋void computermove(char board[ROW][COL], int row, int col); //电脑下棋void game1(char board[ROW][COL], int row, int col); //人机模式void game2(char board[ROW][COL], int row, int col); //人人模式int Ifwin(char board[ROW][COL], int row, int col, int x, int y); //判断输赢int check_x(char board[ROW][COL], int row, int col, int x, int y); //判断竖直五子int check_y(char board[ROW][COL], int row, int col, int x, int y); //判断水平五子int check_xy_up(char board[ROW][COL], int row, int col, int x, int y); //判断斜上五子int check_xy_down(char board[ROW][COL], int row, int col, int x, int y); //判断斜下五子

三、menu菜单函数

void menu(){//完成菜单的初始化 printf("***********************\n"); printf("***********************\n"); printf("*****1.play0.exit****\n"); printf("***********************\n"); printf("***********************\n"); printf("请输入："); }

很简单，就不多说了
四、初始化棋盘Initboard函数
初始化棋盘，为数组一一存入空格

void Initboard(char board[ROW][COL], int row, int col){ int i = 0; int j = 0; for (i = 0; i < row; i++) {for (j = 0; j < col; j++){board[i][j] = ' '; } }}

五、显示棋盘Displayboard函数
打印简单的方格线，并打印数据内容

void Displayboard(char board[ROW][COL], int row, int col){ int i = 0; int j = 0; for (j = 0; j < col; j++)//打印横向y坐标 {if (j == 0)//考虑到x轴所占的一格{printf("%d", j + 1); }else{printf(" %d", j + 1); } } printf("\n"); for (i = 0; i < row; i++)//打印数据 { for (j = 0; j < col; j++){if (j == 0)//顺带打印竖向x坐标{printf("%2d",i+1); //%md表示域宽为mprintf("%c ",board[i][j]); }else{printf(" %c ", board[i][j]); }if (j < col - 1)printf("|"); }printf("\n"); //打印分割行if (i < row - 1){for (j = 0; j < col; j++){if (j == 0)//同样考虑到y轴printf("---"); elseprintf("---"); if (j < col - 1)printf("|"); }printf("\n"); } } }

六、落子函数
【利用C语言实现五子棋游戏】玩家一落子——playermove_1

void Playermove_1(char board[ROW][COL], int row, int col, int *px, int*py)//ROW可以省，COL不行{ int x = *px; int y = *py; while (1) {if (x >= 1 && x <= row && y >= 1 && y <= col)//判断输入坐标的合法性{if (board[x -1][y- 1] == ' ')//保证落子点为空{board[x-1 ][y -1] = '*'; *px = x; *py = y; //如果开始xy输入不合法，则要对外部xy修改，所以选择传址操作break; }else{printf("你不能在此处落子\n"); printf("玩家1落子，请重新输入x y坐标： "); scanf("%d%d", &x, &y); }}else{printf("输入坐标不合法\n"); printf("玩家落子，请重新输入x y坐标： "); scanf("%d%d", &x, &y); } } }

玩家2落子完全相同，就不赘叙了
电脑落子

void computermove(char board[ROW][COL], int row, int col){ int x = 0; int y = 0; //rand函数的使用需要srand函数的初始化，但srand不可以被重复调用，所以放在外部 while (1) {x = rand() % ROW; y = rand() % COL; if (board[x][y] == ' ')//x的范围在0~row-1，所以这里x不用-1了{board[x][y] = '#'; break; } } }

七、判断输赢ifwin
根据我们下五子棋的经验，能获胜的地方必定是最后落子的水平线、竖直线、和两个斜对角线，我们只需对其进行检索即可。ifwin的返回值决定之后的switch语句
弱弱的说一句，虽然看起来多，但很多都是重复的。

int Ifwin(char board[ROW][COL], int row, int col, int x, int y){ int ret; {ret = check_x(board, row, col, x, y); if (ret >= 5)return 0; ret = check_y(board, row, col, x, y); if (ret >= 5)return 0; ret = check_xy_up(board, row, col, x, y); if (ret >= 5)return 0; ret = check_xy_down(board, row, col, x, y); if (ret >= 5)return 0; } return 3; } int check_x(char board[ROW][COL], int row, int col, int x, int y)//检查x轴竖直方向{ int sum = 1; int old_x = x; while (x < row&& board[x - 1][y - 1] == board[x][y - 1]) {sum++; x++; } x = old_x; while (x-2>= 0 && board[x - 1][y - 1] == board[x - 2][y - 1] ) {sum++; x--; } return sum; } int check_y(char board[ROW][COL], int row, int col, int x, int y)//检查y轴水平方向{ int sum = 1; int old_y = y; while (y= 0 && board[x-1][y-1] == board[x-1][y -2]) {sum++; y--; } return sum; } int check_xy_up(char board[ROW][COL], int row, int col, int x, int y)//检查斜上45度{ int sum = 1; int old_x = x; int old_y = y; while (x= 0 && board[x - 1][y - 1] == board[x][y - 2]) {sum++; x++; y--; } x = old_x; y = old_y; while (x - 2 >= 0 && y =0&& y-2 >=0) {sum++; x--; y--; } return sum; }

八、人机、人人模式的选择
初始选择界面

void game(){ int input; char board[ROW][COL] = { 0 }; Initboard(board, ROW, COL); //初始化棋盘 Displayboard(board, ROW, COL); //展示棋盘 printf("请选择模式：1.人机；2.玩家对战\n"); printf("请选择："); do{scanf("%d", &input); printf("\n"); switch (input){case 1:printf("游戏模式1开始!（注意：竖为x轴，横为y轴）\n"); game1(board, ROW, COL); break; case 2:printf("游戏模式2开始!（注意：竖为x轴，横为y轴）\n"); ; game2(board, ROW, COL); break; default:printf("请重新输入\n"); break; } } while (input != 1 && input != 2); //do while语句在输入错误时反复输入}

game1的具体实现

void game1(char board[ROW][COL], int row, int col){ srand((unsigned int)time(NULL)); //srand只要设置一次就可以，所以要放在while循环外 while (1) {int ret; int count = 0; int flag = 0; //判读玩家的下棋int x; int y; printf("玩家落子，请依次输入x y坐标： "); scanf("%d%d", &x, &y); Playermove_1(board, row, col,&x, &y); count++; Displayboard(board, ROW, COL); if (count == ROW*COL)//全下满则认为平局ret = 1; else ret = Ifwin(board, ROW, COL, x, y); switch (ret){case 0:printf("玩家获胜\n"); flag = 1; break; case1:printf("平局\n"); flag = 1; break; default: break; }if (flag == 1)//用flag跳出while循环break; //判断计算机的下棋computermove(board, row, col); count++; Displayboard(board, ROW, COL); if (count == ROW*COL)ret = 1; elseret = Ifwin(board, ROW, COL, x, y); switch (ret){case 0:printf("电脑获胜\n"); flag = 1; break; case1:printf("平局\n"); flag = 1; break; default: break; }if (flag == 1)break; } }

作者觉得写的是挺啰嗦，欢迎留言建议。game2和game1玩家一的内容很相近，就不赘述
九、作者遇到的坑点
1.输入的坐标和存在数组里的下标有减一的关系，在写的时候不要写忘记了
2.传址操作才能改变函数外的变量值
十、完整的代码
头文件就省了

int main(){ int input; do{system("cls"); //清屏menu(); scanf("%d", &input); switch (input){case 1:printf("游戏开始\n\n"); game(); break; case 0:printf("退出游戏\n"); break; default:printf("请重新输入\n"); break; }Sleep(3000); //暂停3秒 } while (input); //do while语句实现可以反复玩 return 0; } void menu(){//完成菜单的初始化 printf("***********************\n"); printf("***********************\n"); printf("*****1.play0.exit****\n"); printf("***********************\n"); printf("***********************\n"); printf("请输入："); } void Initboard(char board[ROW][COL], int row, int col){ int i = 0; int j = 0; for (i = 0; i < row; i++) {for (j = 0; j < col; j++){board[i][j] = ' '; } }} void Displayboard(char board[ROW][COL], int row, int col){ int i = 0; int j = 0; for (j = 0; j < col; j++)//打印横向y坐标 {if (j == 0)//考虑到x轴所占的一格{printf("%d", j + 1); }else{printf(" %d", j + 1); } } printf("\n"); for (i = 0; i < row; i++)//打印数据 { for (j = 0; j < col; j++){if (j == 0)//顺带打印竖向x坐标{printf("%2d",i+1); //%md表示域宽为mprintf("%c ",board[i][j]); }else{printf(" %c ", board[i][j]); }//数字表示坐标if (j < col - 1)printf("|"); }printf("\n"); //打印分割行if (i < row - 1){for (j = 0; j < col; j++){if (j == 0)//同样考虑到y轴printf("---"); elseprintf("---"); if (j < col - 1)printf("|"); }printf("\n"); //别忘记这里也要换行 } } } void game(){ int input; char board[ROW][COL] = { 0 }; Initboard(board, ROW, COL); //初始化棋盘 Displayboard(board, ROW, COL); //展示棋盘 printf("请选择模式：1.人机；2.玩家对战\n"); printf("请选择："); do{scanf("%d", &input); printf("\n"); switch (input){case 1:printf("游戏模式1开始!（注意：竖为x轴，横为y轴）\n"); game1(board, ROW, COL); break; case 2:printf("游戏模式2开始!（注意：竖为x轴，横为y轴）\n"); ; game2(board, ROW, COL); break; default:printf("请重新输入\n"); break; } } while (input != 1 && input != 2); //do while语句在输入错误时反复输入} void game1(char board[ROW][COL], int row, int col){ srand((unsigned int)time(NULL)); //srand只要设置一次就可以，所以要放在while循环外 while (1) {int ret; int count = 0; int flag = 0; //判读玩家的下棋int x; int y; printf("玩家落子，请依次输入x y坐标： "); scanf("%d%d", &x, &y); Playermove_1(board, row, col,&x, &y); count++; Displayboard(board, ROW, COL); if (count == ROW*COL)//全下满则认为平局ret = 1; else ret = Ifwin(board, ROW, COL, x, y); switch (ret){case 0:printf("玩家获胜\n"); flag = 1; break; case1:printf("平局\n"); flag = 1; break; default: break; }if (flag == 1)//用flag跳出while循环break; //判断计算机的下棋computermove(board, row, col); count++; Displayboard(board, ROW, COL); if (count == ROW*COL)ret = 1; elseret = Ifwin(board, ROW, COL, x, y); switch (ret){case 0:printf("电脑获胜\n"); flag = 1; break; case1:printf("平局\n"); flag = 1; break; default: break; }if (flag == 1)break; } } void game2(char board[ROW][COL], int row, int col){ while (1) {int ret; int count = 0; int flag = 0; int x; int y; //判读玩家1的下棋printf("玩家1落子，请输入坐标:（注意：竖为x轴，横为y轴）"); scanf("%d%d", &x, &y); Playermove_1(board, row, col, &x, &y); count++; Displayboard(board, ROW, COL); if (count == ROW*COL)ret = 1; elseret = Ifwin(board, ROW, COL, x, y); switch (ret){case 0:printf("玩家1获胜\n"); flag = 1; break; case1:printf("平局\n"); flag = 1; break; default: break; }if (flag == 1)break; //判断玩家2的下棋printf("玩家2落子，请输入坐标:（注意：竖为x轴，横为y轴）"); scanf("%d%d", &x, &y); Playermove_2(board, row, col, &x, &y); count++; Displayboard(board, ROW, COL); if (count == ROW*COL)ret = 1; elseret = Ifwin(board, ROW, COL, x, y); switch (ret){case 0:printf("玩家2获胜\n"); flag = 1; break; case1:printf("平局\n"); flag = 1; break; default: break; }if (flag == 1)break; } } void Playermove_1(char board[ROW][COL], int row, int col, int *px, int*py)//ROW可以省，COL不行{ int x = *px; int y = *py; while (1) {if (x >= 1 && x <= row && y >= 1 && y <= col)//判断输入坐标的合法性{if (board[x -1][y- 1] == ' ')//保证落子点为空{board[x-1 ][y -1] = '*'; *px = x; *py = y; //如果开始xy输入不合法，要对外部xy修改，所以要传址操作break; }else{printf("你不能在此处落子\n"); printf("玩家1落子，请重新输入x y坐标： "); scanf("%d%d", &x, &y); }}else{printf("输入坐标不合法\n"); printf("玩家落子，请重新输入x y坐标： "); scanf("%d%d", &x, &y); } } } void Playermove_2(char board[ROW][COL], int row, int col, int *px, int*py){ int x = *px; int y = *py; while (1) {if (x >= 1 && x <= row && y >= 1 && y <= col)//判断输入坐标的合法性{if (board[x - 1][y - 1] == ' ')//保证落子点为空{board[x - 1][y - 1] = '#'; *px = x; *py = y; break; }else{printf("你不能在此处落子\n"); printf("玩家2落子，请重新输入x y坐标： "); scanf("%d%d", &x, &y); }}else{printf("输入坐标不合法\n"); printf("玩家落子，请重新输入x y坐标： "); scanf("%d%d", &x, &y); } } } void computermove(char board[ROW][COL], int row, int col){ int x = 0; int y = 0; while (1) {x = rand() % ROW; y = rand() % COL; if (board[x][y] == ' '){board[x][y] = '#'; break; } } } int Ifwin(char board[ROW][COL], int row, int col, int x, int y){ int ret; {ret = check_x(board, row, col, x, y); if (ret >= 5)return 0; ret = check_y(board, row, col, x, y); if (ret >= 5)return 0; ret = check_xy_up(board, row, col, x, y); if (ret >= 5)return 0; ret = check_xy_down(board, row, col, x, y); if (ret >= 5)return 0; } return 3; } int check_x(char board[ROW][COL], int row, int col, int x, int y)//检查x轴竖直方向{ int sum = 1; int old_x = x; while (x < row&& board[x - 1][y - 1] == board[x][y - 1]) {sum++; x++; } x = old_x; while (x-2>= 0 && board[x - 1][y - 1] == board[x - 2][y - 1] ) {sum++; x--; } return sum; } int check_y(char board[ROW][COL], int row, int col, int x, int y)//检查y轴水平方向{ int sum = 1; int old_y = y; while (y= 0 && board[x-1][y-1] == board[x-1][y -2]) {sum++; y--; } return sum; } int check_xy_up(char board[ROW][COL], int row, int col, int x, int y)//检查斜上45度{ int sum = 1; int old_x = x; int old_y = y; while (x= 0 && board[x - 1][y - 1] == board[x][y - 2]) {sum++; x++; y--; } x = old_x; y = old_y; while (x - 2 >= 0 && y =0&& y-2 >=0) {sum++; x--; y--; } return sum; }

如果对你有帮助和启发，作者感到很高兴。
以上就是本文的全部内容，希望对大家的学习有所帮助，也希望大家多多支持脚本之家。