本文来源于两个简单的题目：
- 判断一对单词是否是" Anagrams "
- 判断信用卡是否合理
anagrams 的百度翻译：由颠倒字母顺序而构成的字（短语）而题目给出例子：
[ DOG , ODG ]
[ DOG , DOG ]
[ DOG , GOD ]
[ DOG , GDO ]
均为 anagrams 。
那思路就简单了，直接拆分字母，排序，比较就 ok 。
判断信用卡 题目给出的要求如下：
The criteria are:样例输出如下：
? It must start with a 4,5 or 6
? It must be exactly 16 digits
? It must be numbers only
? It can have a digits in groups of 4, separated by one hyphen “-“
? It should not contain any other characters.
? It must NOT have any 4 repeated digits.
378282246310005 Invalidpy文件 两个题目合并在一个 py 文件中。
30569309025904 Invalid
6011111111111117 Invalid
5123-2332-3232-3213 valid
而入参数分别是两个文件的名字，一个是 anagram.txt ，另一个是 credit_cards.txt ，他们分别长这样：
文章图片
文章图片
【python利用正则筛选信用卡】最后的程序长这样：
#! /usr/bin/python3
import re
###############################
##You need to implet the following methods:
##
##Question 1
##anagram_validator()
##
##Question 2
##credit_card_validator()###################################################################################
# Question 1: Check for anagrams:#
###################################################def get_list(src_str):
sub_list=[]
word_tmp=''
for word in src_str:
if word != ',':
word_tmp = word_tmp+word
else:
sub_list.append(word_tmp)
word_tmp = ''
return sub_listdef read_anagram(file_name):
'''
Input: a file name
Return: a nested list of two words list
Example : [[word1,word2],[word3,word4]...etc]
'''
with open(file_name,encoding = 'utf-8') as f:
return_list =[]
file_conment = f.read()file_conment_new = re.sub(r'\n',',',file_conment)
file_conment_new = file_conment_new+','
subs_list = get_list(file_conment_new)
i=0
while i < (len(subs_list)-1):
return_list.append([subs_list[i],subs_list[i+1]])
i=i+2
return return_listdef anagram_validator(anagram):
'''
Input is the output from "read_anagram()".
Return: list of "anagrams" or "Not anagrams" values for each two words
example input (dog,gdo),(try,elm) then output would be ["anagrams","Not anagrams"] with sequence of the input
'''
result_list=[]
for i in range(len(anagram)):
word_font = ''.join((lambda x:(x.sort(),x)[1])(list(anagram[i][0])))
word_back = ''.join((lambda x:(x.sort(),x)[1])(list(anagram[i][1])))
if word_font == word_back:
result_list.append('Anagrams')
else:
result_list.append('Not anagrams')return result_list############################################
# Question 2: Validate credit cards#
############################################
def read_credit_cards(file_name):
'''
Input: a file name
Return tuple of numbers
'''
with open(file_name,encoding='utf-8') as f:
card_conment = f.read()card_conment = re.sub(r'\[','',card_conment)
card_conment = re.sub(r'\]','',card_conment)
card_conment = card_conment+','
card_list = get_list(card_conment)
return tuple(card_list)def credit_card_validator(numbers):
'''
Input: tuple of numbers
Return:dictionary of credit card numbers where key is the number and value if valid or invalid
'''
validator_list=[]
credit_dict={}
for i in range(len(numbers)):
validator_list.append(numbers[i])for i in range(len(numbers)):
ch_num = 0
repeat_flag = 0
for ch in validator_list[i]:
iford("A")<=ord(ch)<=ord("Z"):
ch_num+=1
breaktmp_list = []
tmp_list = (re.sub(r"[^\d]", "", validator_list[i]))
for index in range(len(tmp_list)-4):
if(tmp_list[index] == tmp_list[index+1] and
tmp_list[index] == tmp_list[index+2] and
tmp_list[index] == tmp_list[index+3] ):
repeat_flag = 1
break;
if(validator_list[i][0] != '4' and
validator_list[i][0] != '5' and
validator_list[i][0] != '6' ):
credit_dict[validator_list[i]]='Invalid'
elif( len(re.sub(r"\D", "", validator_list[i])) != 16 ):
credit_dict[validator_list[i]]='Invalid'
elif(ch_num > 0):
credit_dict[validator_list[i]]='Invalid'
elif(
(re.search(r"-",validator_list[i])) and
( validator_list[i][4] != '-' or
validator_list[i][9] != '-'or
validator_list[i][14] != '-'
)
):
credit_dict[validator_list[i]]='Invalid'
elif(re.search(r"[^-\d]",validator_list[i])):
credit_dict[validator_list[i]]='Invalid'
elif(repeat_flag == 1 ):
credit_dict[validator_list[i]]='Invalid'
else :
credit_dict[validator_list[i]]='Valid'
space_str = ''return credit_dictdef print_credit_card_summary(dict_o):
'''
Input: dict
Return:
printing summary of validation result - space between credit card and status is 40 width
example:
378282246310005Invalid
30569309025904Invalid
'''
space_str = ''
for key in dict_o:
new_str = key + dict_o[key]
if(dict_o[key] == "Valid"):
new_str_tmp = new_str[:-5]
space_lenth = 46-len(new_str)
for x in range(space_lenth):
space_str +=' '
print(new_str_tmp + space_str + 'Valid')
space_str=''
else :
new_str_tmp = new_str[:-7]
space_lenth = 48-len(new_str)
for x in range(space_lenth):
space_str +=' '
print(new_str_tmp + space_str + 'Invalid')
space_str='' ####### THE CODE BELOW IS FOR TESTING###################
############### DO NOTCHANGE #########################import sysif __name__ == '__main__':
# Take care of the console inputs
if len(sys.argv) <= 1:
sys.argv = ['', "anagram.txt", "credit_cards.txt"]
stars = '*' * 40
print(stars)
print("Testing Question 1 --- Anagrams?")
print(stars)# testing reading_anagrams
try:
anagram = read_anagram(sys.argv[1])
if not anagram:
print("read_anagram() returns None.")
else:
print("anagram: ", anagram)
print()
except Exception as e:
print("Error (readnumbers()): ", e)# testing anagram_validator
Anagrams = 0
NAnagrams = 0
try:
if not anagram:# Question 1 has not been implemented
print("anagram_validator() skipped....")
else:
result = anagram_validator(anagram)
if result == None:
print("anagram_validator() returns None.")
else:
for i in result:
if i == "Anagrams":
Anagrams += 1
elif i == "Not anagrams":
NAnagrams += 1
print("Number of valid Anagrams is {} and Not anagrams is {}.".format(Anagrams, NAnagrams))except Exception as e:
print("Error (anagram_validator()):", e)# testingQuestion 2
print("\n\n" + stars)
print("Testing Question 2 --- Credit Card Validator")
print(stars)# Testing reading_credit_cards
try:
tup = read_credit_cards(sys.argv[2])
if not tup:
print("read_credit_cards() returns None.")
else:
print("The tuple of credit_cards: {}".format(tup))
except Exception as e:
print("Error (read_credit_cards()):", e)# Testing credit_card_validator
vcc = 0
ivcc = 0
try:
if not tup:# Readin_Question 2 has not been implemented
print("credit_card_validator() skipped...")
else:
cc_dict = credit_card_validator(tup)
tmp_cc_dict = cc_dict
if not cc_dict:
print("credit_card_validator()returns None.")
else:
for items in cc_dict.keys():
if cc_dict[items] == "Valid":
vcc += 1
elif cc_dict[items] == "Invalid":
ivcc += 1
print("Number of valid credit cards is {} and invalid {}.".format(vcc, ivcc))
except Exception as e:
print("Error (credit_card_validator()):", e)# testingQuestion 2
print("\n\n" + stars)
print("Testing Question 2b --- Print Credit Card Summary")
print(stars)
# Testing print_credit_card_summary
try:
if not tmp_cc_dict:# Dict credit card output has not been implemented
print("print_credit_card_summary() skipped...")
else:
import io# do not delete this line
from contextlib import redirect_stdout# do not delete this linef = io.StringIO()
with redirect_stdout(f):
print_credit_card_summary(tmp_cc_dict)
out = f.getvalue()
if not out:
print("print_credit_card_summary()returns None.")
else:
count44 = 0
count46 = 0
for line in out.splitlines():
if len(line) - len(line.split()) == 44:
count44 += 1
elif len(line) - len(line.split()) == 46:
count46 += 1
if count44 == vcc and count46 == ivcc:
print("Your format looks good")
else:
print("You might have some issues in your summary format")except Exception as e:
print("Error (print_credit_card_summary()):", e)推荐阅读
- 推荐系统论文进阶|CTR预估 论文精读(十一)--Deep Interest Evolution Network(DIEN)
- Python专栏|数据分析的常规流程
- Python|Win10下 Python开发环境搭建(PyCharm + Anaconda) && 环境变量配置 && 常用工具安装配置
- Python绘制小红花
- Pytorch学习|sklearn-SVM 模型保存、交叉验证与网格搜索
- OpenCV|OpenCV-Python实战（18）——深度学习简介与入门示例
- python|8. 文件系统——文件的删除、移动、复制过程以及链接文件
- 爬虫|若想拿下爬虫大单，怎能不会逆向爬虫，价值过万的逆向爬虫教程限时分享
- 分布式|《Python3网络爬虫开发实战（第二版）》内容介绍
- java|微软认真聆听了开源 .NET 开发社区的炮轰（ 通过CLI 支持 Hot Reload 功能）