golang|golang strings Replace 字符串替换 golangstringsReplace字符串替换

函数声明为：

func Replace(s, old, new string, n int) string

官方描述为：返回将s中前n个不重叠old子串都替换为new的新字符串，如果n<0会替换所有old子串。
示例代码为，每行的结果见每行上面的注释部分：

func main() { // non-overlapping: "123" repeat 6 times in s s := "123lafaldsjglad123lkfasdf123djfal123lkdjga123lksjfla123l" old := "123" new := "888"fmt.Println("non-overlapping: ") // n < 0 ,用 new 替换所有匹配上的 old；n=-1:888lafaldsjglad888lkfasdf888djfal888lkdjga888lksjfla888l fmt.Println("n=-1: ", strings.Replace(s, old, new, -1 ))// 不替换任何匹配的 old；n=0:123lafaldsjglad123lkfasdf123djfal123lkdjga123lksjfla123l fmt.Println("n=0: ", strings.Replace(s, old, new, 0 )) // 用 new 替换第一个匹配的 old；n=1:888lafaldsjglad123lkfasdf123djfal123lkdjga123lksjfla123l fmt.Println("n=1: ", strings.Replace(s, old, new, 1 ))// 用 new 替换前 5 个匹配的 old（实际多于 5 个）；n=5:888lafaldsjglad888lkfasdf888djfal888lkdjga888lksjfla123l fmt.Println("n=5: ", strings.Replace(s, old, new, 5 )) // 用 new 替换前 7 个匹配上的 old（实际没那么多）；n=7:888lafaldsjglad888lkfasdf888djfal888lkdjga888lksjfla888l fmt.Println("n=7: ", strings.Replace(s, old, new, 7 )) // overlapping: s = "888888888888888888" old = "888" new = "666" fmt.Println("overlapping: ")// n < 0 ,用 new 替换所有匹配上的 old；n=-1:666666666666666666 fmt.Println("n=-1: ", strings.Replace(s, old, new, -1 )) // 不替换任何匹配的 old；n=0:888888888888888888 fmt.Println("n=0: ", strings.Replace(s, old, new, 0 )) // 用 new 替换第一个匹配的 old；n=1:666888888888888888 fmt.Println("n=1: ", strings.Replace(s, old, new, 1 )) // 用 new 替换前 5 个匹配的 old（实际多于 5 个）；n=5:666666666666666888 fmt.Println("n=5: ", strings.Replace(s, old, new, 5 ))// 用 new 替换前 7 个匹配上的 old（实际没那么多）；n=7:666666666666666666 fmt.Println("n=7: ", strings.Replace(s, old, new, 7 )) }

【golang|golang strings Replace 字符串替换】