python数字转对应中文的方法总结 python数字转对应中文的方法总

本文操作环境：

windows7系统，DELL G3电脑，python3.5版

python实现将阿拉伯数字转换成中文
第一种转换方式:

1-->一12-->一二def num_to_char(num):"""数字转中文"""num=str(num)new_str=""num_dict={"0":u"零","1":u"一","2":u"二","3":u"三","4":u"四","5":u"五","6":u"六","7":u"七","8":u"八","9":u"九"}listnum=list(num)# print(listnum)shu=[]for i in listnum:# print(num_dict[i])shu.append(num_dict[i])new_str="".join(shu)# print(new_str)return new_str

第二种转换方式:

1-->一12-->十二23-->二十三_MAPPING = (u'零', u'一', u'二', u'三', u'四', u'五', u'六', u'七', u'八', u'九', u'十', u'十一', u'十二', u'十三', u'十四', u'十五', u'十六', u'十七',u'十八', u'十九')_P0 = (u'', u'十', u'百', u'千',)_S4 = 10 ** 4def _to_chinese4(num):assert (0 <= num and num < _S4)if num < 20:return _MAPPING[num]else:lst = []while num >= 10:lst.append(num % 10)num = num / 10lst.append(num)c = len(lst)# 位数result = u''for idx, val in enumerate(lst):val = int(val)if val != 0:result += _P0[idx] + _MAPPING[val]if idx < c - 1 and lst[idx + 1] == 0:result += u'零'return result[::-1]

实例扩展：

#!/usr/bin/python#-*- encoding: utf-8 -*-import typesclass NotIntegerError(Exception):passclass OutOfRangeError(Exception):pass_MAPPING = (u'零', u'一', u'二', u'三', u'四', u'五', u'六', u'七', u'八', u'九', )_P0 = (u'', u'十', u'百', u'千', )_S4, _S8, _S16 = 10 ** 4 , 10 ** 8, 10 ** 16_MIN, _MAX = 0, 9999999999999999def _to_chinese4(num):'''转换[0, 10000)之间的阿拉伯数字'''assert(0 <= num and num < _S4)if num < 10:return _MAPPING[num]else:lst = [ ]while num >= 10:lst.append(num % 10)num = num / 10lst.append(num)c = len(lst)# 位数result = u''for idx, val in enumerate(lst):if val != 0:result += _P0[idx] + _MAPPING[val]if idx < c - 1 and lst[idx + 1] == 0:result += u'零'return result[::-1].replace(u'一十', u'十')def _to_chinese8(num):assert(num < _S8)to4 = _to_chinese4if num < _S4:return to4(num)else:mod = _S4high, low = num / mod, num % modif low == 0:return to4(high) + u'万'else:if low < _S4 / 10:return to4(high) + u'万零' + to4(low)else:return to4(high) + u'万' + to4(low)def _to_chinese16(num):assert(num < _S16)to8 = _to_chinese8mod = _S8high, low = num / mod, num % modif low == 0:return to8(high) + u'亿'else:if low < _S8 / 10:return to8(high) + u'亿零' + to8(low)else:return to8(high) + u'亿' + to8(low)def to_chinese(num):if type(num) != types.IntType and type(num) != types.LongType:raise NotIntegerError(u'%s is not a integer.' % num)if num < _MIN or num > _MAX:raise OutOfRangeError(u'%d out of range[%d, %d)' % (num, _MIN, _MAX))if num < _S4:return _to_chinese4(num)elif num < _S8:return _to_chinese8(num)else:return _to_chinese16(num)if __name__ == '__main__':print to_chinese(9000)

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