C语言代码实现井字棋游戏

井字棋是一个很常见的小游戏。要求对战双方在一个“井”形的棋盘里分别下“*”棋子或者“#”棋子,谁先连成3个,谁就赢。
本次使用C语言来实现这个小游戏。
由于使用函数较多,所以采用多文件的方式方便梳理代码思路。
本次一共有三个文件:
**
game.h:
包含了game.c文件中函数的声明和库函数的声明。**

#pragma once#define ROW 3#define COL 3#include#include#includevoid InitBoard(char board [ROW][COL], int row, int col); //初始化棋盘void DisplayBoard(char board [ROW][COL], int row, int col); //打印棋盘void PlayerBoard(char board [ROW][COL], int row, int col); //玩家走void ComputerBoard(char board [ROW][COL], int row, int col); //电脑走char IsWin(char board [ROW][COL], int row, int col); //结果判断

game.c:
【C语言代码实现井字棋游戏】包含游戏过程中关键函数的函数主体。
#define _CRT_SECURE_NO_WARNINGS#include"game.h"void InitBoard(char board[ROW][COL], int row, int col){ //初始化棋盘 int i = 0; for (i = 0; i < row; i++) {int j = 0; for (j = 0; j < col; j++)board [i][j] = ' '; }}void DisplayBoard(char board [ROW][COL], int row, int col){ //打印棋盘 int i = 0; for (i = 0; i < row; i++) {int j = 0; for (j = 0; j < col; j++){printf(" %c ", board [i][j]); if (j < col - 1)printf("|"); }printf("\n"); if (i < row - 1){for (j = 0; j < col; j++){printf("---"); if (j < col - 1)printf("|"); }printf("\n"); } }}void PlayerBoard(char board [ROW][COL], int row, int col){ int x = 0, y = 0; while (1) {printf("输入棋子坐标->"); scanf("%d%d", &x, &y); if (x > 0 && x <= row && y > 0 && y <= col){if (board [x - 1][y - 1] == ' '){board [x - 1][y - 1] = '*'; break; }else{printf("此位置已有棋子!请重新输入。\n"); }}else{printf("输入错误!请重新输入。\n"); } }}void ComputerBoard(char board [ROW][COL], int row, int col){ int x = 0, y = 0; while (1) {x = rand() % row; y = rand() % col; if (board [x][y] != ' '){continue; }else{board [x][y] = '#'; break; } }}int IsFull(char board [ROW][COL], int row, int col){ int i = 0; for (i = 0; i < row; i++) {int j = 0; for (j = 0; j < col; j++){if (board [i][j] == ' ')return 0; } } return 1; }char IsWin(char board [ROW][COL], int row, int col){ int i = 0; //行 for (i = 0; i < row; i++) {if (board [i][0] == board [i][1] && board [i][1] == board [i][2] && board [i][0] != ' ')return board [i][0]; } //列 for (i = 0; i < col; i++) {if (board [0][i] == board [1][i] && board [1][i] == board [2][i] && board [0][i] != ' ')return board [0][i]; } //对角线 if (board [0][0] == board [1][1] && board [1][1] == board [2][2] & board [1][1] != ' ')return board [1][1]; if (board [2][0] == board [1][1] && board [1][1] == board [0][2] & board [1][1] != ' ')return board [1][1]; //是否平局 if (IsFull(board, row, col))return 'Q'; //平局 return 'C'; //继续}

test.c:
main函数和游戏的大概流程。
#define _CRT_SECURE_NO_WARNINGS#include"game.h"void Menu(){ printf("*******************************\n"); printf("**********1、play**********\n"); printf("**********0、quit**********\n"); printf("*******************************\n"); }void game(){ char board [ROW][COL]; InitBoard(board, ROW, COL); DisplayBoard(board, ROW, COL); char ret = 0; srand((unsigned int) time(NULL)); while (1) {printf("玩家走\n"); PlayerBoard(board, ROW, COL); DisplayBoard(board, ROW, COL); ret = IsWin(board, ROW, COL); if (ret != 'C')break; printf("电脑走\n"); ComputerBoard(board, ROW, COL); DisplayBoard(board, ROW, COL); ret = IsWin(board, ROW, COL); if (ret != 'C')break; } if (ret == '*')printf("玩家胜利!\n"); else if (ret == '#')printf("电脑胜利!\n"); elseprintf("平局!\n"); }int main(){ //三子棋 int input = 1; while (input) {Menu(); printf("输入1开始游戏,输入0退出游戏。\n请输入->"); scanf("%d", &input); switch(input){case 1:game(); printf("开始游戏\n"); break; case 0:printf("游戏结束\n"); break; default:printf("非法输入,请重试!\n"); } } return 0; }

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C语言代码实现井字棋游戏
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C语言代码实现井字棋游戏
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