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像素点运算java源代码 像素点运算java源代码是什么

IT技术解决问题

java 中如何获取 Panel 上某个像素点的 颜色java中获取Panel上某个像素点的像素颜色，代码如下：
public static void main(String[] args) {
//创建一个150*150，RGB高彩图，类型可自定
BufferedImage img=new BufferedImage(150, 150, BufferedImage.TYPE_INT_rgb);
//取得图形
Graphics g=img.getGraphics();
【像素点运算java源代码 像素点运算java源代码是什么】 //设置黑色（black）
g.setColor(Color.BLACK);
//填充颜色
g.fillRect(0, 0, img.getWidth(), img.getHeight());
//在D盘创建个一个png格式图片
File file=new File("D:/zhidao.png");
try{
//以png方式写入，可改成jpg、gif等其它后缀图片
ImageIO.write(img, "PNG", file);
}catch (IOException e){
e.printStackTrace();
}
//D盘上就生成了一个zhidao.png的黑色图片
}

(Java程序题)输入一个5*5的矩阵(图片), 矩阵边的像素点值不变, 我的代码在下面，结果运行不行？首先像素点运算java源代码你判断定位像素点运算java源代码的条件错了，还有就是你想输出4.2 4.8 这样的小数，你用int类型绝对会都输出4
如何用java编程实现提取一张图像每个像素点的灰度，并且按顺序输出为一串数字代码？用个HashMap存储信息到文件像素点运算java源代码，可以像素点运算java源代码的话那么代码如下:
import java.util.*
import java.io.*
public class Test1
用java将二进制黑白像素点，画在正方形中import java.applet.*;
import java.awt.*;
import java.awt.geom.*;
public class Text extends Applet
{
public void paint(Graphics g)
{
g.drawRect(0 ,0, 28,28);//画正方形
g.drawLine(3, 3, 9, 3);
g.drawLine(3, 3, 3, 9);
g.drawLine(5, 5, 9, 5);
g.drawLine(5, 5, 5, 9);
g.drawLine(7, 7, 9, 7);
g.drawLine(7, 7, 7, 9);
g.drawLine(8, 8, 9, 8);
g.drawLine(8, 8, 8 ,9);
g.drawLine(9, 9, 9, 9);
g.drawLine(25,3, 19, 3);
g.drawLine(25,3, 25,9);
g.drawLine(23,5, 19, 5);
g.drawLine(23,5, 23,9);
g.drawLine(21,7, 19, 7);
g.drawLine(21,7, 21,9);
g.drawLine(20,8, 19, 8);
g.drawLine(20,8, 20,9);
g.drawLine(19,9,19,9);
g.drawLine(3, 25, 5,25);
g.drawLine(3, 25, 3,23);
g.drawLine(4, 25, 5,25);
g.drawLine(4, 25, 4,23);
g.drawLine(5, 25, 5,25);
g.drawLine(5, 25, 5,23);
g.drawLine(7, 25, 7,21);
g.drawLine(3, 21, 7,21);
g.drawLine(9,25, 9,19);
g.drawLine(9,19,3,19);
g.drawLine(25,25,25,19);
g.drawLine(25,25,19,25);
g.drawLine(23,23,23,19);
g.drawLine(23,23,19,23);
g.drawLine(21,21,21,19);
g.drawLine(21,21,19,21);
g.drawLine(20,20,20,19);
g.drawLine(20,20,19,20);
g.drawLine(19,19,19,19);//画四个角的寻像图像
char[] c={1,1,1,1,1,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0};
//输入一char型的字符串，实际上应该由程序1中获得
{
int j=3;
int i=12;
{
for (int n=0;n=4;n++)
switch (c[n])
{
case(1):
g.drawLine(n+i,j,n+i,j);
}
}
}//如果a[n]为1，则在正方形中画一个黑色像素点，i，j分别为正方形的横.纵坐标
//正方形是23*23像素的，一行画完了接着画下一行，底下的全是重复的画点程序，是按一行一行画的
{
int j=4;
int i=12;
{
for (int n=5;n=9;n++)
switch (c[n])

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