vb.net获取年,月,日,时,分,秒不是 有 函数嘛?
now() 就是 吧
取得 后 再 分离出你所需的,分别赋值 就行了,当然 还是 有 函数的
vb.net中怎么获取日期中的年月日时分秒Dim ThisDay As String = Format(Now, "yyyy-MM-dd")'获得当前日期字符串
Dim ThisDateTime As DateTime = Convert.ToDateTime(ThisDay)'当前日期转换成DateTime
Dim ThisWeekDay As Integer = ThisDateTime.DayOfWeek'获得当前日期是星期几
Dim differadd As Integer = 1 - ThisWeekDay'相差的天数(星期1与当前星期几相差的天数)
Dim MyAdd As New TimeSpan(differadd, 0, 0, 0)
Dim MyYear As Integer = Format(Now, "yyyy")'获取当前日期的年份
Dim MyMonth As Integer = Format(Now, "MM")'获取当前日期的月份
Dim MyDay As Integer = Format(Now, "dd")'获取当前日期是几号
Dim MyToday As DateTime = New DateTime(MyYear, MyMonth, MyDay)
Dim Yourday As DateTime = MyToday.Add(MyAdd)
MsgBox("本周星期一的日期是:"Yourday)
在vb.net中,如何计算出2000-2100年之间的闰年?输出到文本框 , 并统计输出闰年的个数?主要是统计个数这样:
Private Sub Button1_Click(sender As Object, e As EventArgs) Handles Button1.Click
Dim leapyears() As Integer = GetLeapYears(2000, 2100)
Dim str As String
Try
Dim count As Integer = UBound(leapyears)1
str = "闰年个数:"count.ToString
For i = 0 To UBound(leapyears)
str= " "leapyears(i).ToString
Next
TextBox1.Text = str
Catch ex As Exception
End Try
End Sub
''' summary
''' 获取指定年份区间中所有闰年组成的数组
''' /summary
''' param name="StartYear"起始年份/param
''' param name="EndYear"结束年份/param
''' returns/returns
''' remarks/remarks
Private Function GetLeapYears(StartYear As Integer, EndYear As Integer) As Integer()
Dim leapyears() As Integer = Nothing
Dim index As Integer = 0
For i = StartYear To EndYear
If (i Mod 400 = 0) Or (i Mod 4 = 0 And i Mod 1000) Then
ReDim Preserve leapyears(index)
leapyears(index) = i
index= 1
End If
Next
Return leapyears
End Function
扩展资料:
注意事项
DateSerial返回包含指定的年、月、日的 Variant (Date) 。
语法:DateSerial(year, month, day)
Private Function MonthToLeapYear(ByVal Yea As Integer) As Boolean
MonthToLeapYear = Day(DateSerial(Yea, 2, 29)) = 29
End Function
Private Sub Command1_Click()
If Len(Text1.Text) = 4 Then
If MonthToLeapYear(Text1.Text) = True Then
Print Text1.Text"年是闰年"
Else
Print Text1.Text"年是平年"
End If
Else
Print "错误:请输入正确的年份!"
End If
End Sub
在VB.NET中进行日期处理时,避免手工判断或计算是个好主意,因为手工计算由于代码的质量问题可能不准确 。可以使用.NET提供的类的功能进行日期处理 。
例如,如果需要判断给定的某年是否闰年 , 可以使用VB.NET的IsLeapYear函数 。下面是如何使用该函数的一个例子:
Private Sub LeapYearCheck()
Dim bLeapYear AsBoolean
bLeapYear = Date.IsLeapYear(Now.Year)
MessageBox.Show(bLeapYear)
bLeapYear = Date.IsLeapYear(2004)
MessageBox.Show(bLeapYear)
End Sub
vb.net中如何获取当前日期所在星期的星期一的具体年月日Dim ThisDay As String = Format(Now, "yyyy-MM-dd")'获得当前日期字符串
Dim ThisDateTime As DateTime = Convert.ToDateTime(ThisDay)'当前日期转换成DateTime
Dim ThisWeekDay As Integer = ThisDateTime.DayOfWeek'获得当前日期是星期几
Dim differadd As Integer = 1 - ThisWeekDay'相差vb.net获取年份的天数(星期1与当前星期几相差vb.net获取年份的天数)
Dim MyAdd As New TimeSpan(differadd, 0, 0, 0)
Dim MyYear As Integer = Format(Now, "yyyy")'获取当前日期的年份
Dim MyMonth As Integer = Format(Now, "MM")'获取当前日期的月份
Dim MyDay As Integer = Format(Now, "dd")'获取当前日期是几号
Dim MyToday As DateTime = New DateTime(MyYear, MyMonth, MyDay)
Dim Yourday As DateTime = MyToday.Add(MyAdd)
MsgBox("本周星期一的日期是vb.net获取年份:"Yourday)
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