vb.net圆周率 vb求圆周率的近似值

VB(BASIC)算法中可以使用圆周率π吗?不能你得先指定π的值比如Private Const PAI As Single = 3.14那么以后你就可以使用 PAI来代替3.14了
怎么用VB计算圆周率?把步骤和公式写清楚Private Sub Command1_Click()
Dim sum As Double, t As Double
sum = 0: t = 1
Do
sum = sum(-1) ^ (t1) / (2 * t - 1)
t = t1
Loop Until Abs((-1) ^ (t1) / (2 * t - 1))10 ^ (-6)
Magbox 4 * sum
End Sub
【vb.net圆周率 vb求圆周率的近似值】其中10^(-6)是计算精度 , 你可以调整,-6改成-8,精度就可增加,不过计算时间较长 。
vb程序中圆周率怎么表达?自己定义个常数,然后在程序中就可以任意调用了,比如:
Const pi As Double = 3.1415927
然后程序里就可以这样:
s = 2 * pi * r
当然pi你可以改成其他名字的,用π也行
如何用vb计算圆周率'采用普遍vb.net圆周率的傅立叶级数展开方法 pi=2 1/3*(2 2/5*(2 3/7*(2 4/9*(2 5/11.....))))))
'输入:需计算的圆周率位数 , 理论精度约30万位
'Add a commandbutton and textbox(multine=true,scrollbars=both) to form1
Option Explicit
Private Sub Command1_Click()
getpi CLng(InputBox("生成多少位数(1-50000)的PI?", "提示", 30000))
End Sub
Sub getpi(Optional ByVal nums As Long = 10000)
nums = nums / 5
Dim max As Long, laptime As Single, result() As String
Dim i As Long, j As Long, t, d As Long, g, k As Long, f()
laptime = Timer
max = 18 * nums
ReDim f(0 To max)
ReDim result(nums)
For i = 0 To max
f(i) = 20000
Next
result(0) = "π="vbCrLf
g = 20000
For j = max To 1 Step -18
t = 0
For i = j To 1 Step -1
t = tf(i) * 100000
d = 2 * i1
f(i) = t - Int(t / d) * d
t = Int(t / d) * i
Next
k = k1
result(k) = Format(Int(gt / 100000) Mod 100000, "00000")
If k Mod 20 = 0 Then result(k) = result(k)vbCrLf
If k Mod 200 = 0 Then result(k) = result(k)"---["k * 5"]---"vbCrLf
g = t Mod 100000
Next
Text1.Text = Join(result, " ")
Me.Caption = "计算完毕vb.net圆周率!总计用时"Timer - laptime"秒!"
End Sub
vb中有没有圆周率这个常量,怎样调用?。?/h2>用符号常量定义
符号常量是用一个符号表示一个固定不变的量.它有两种来源:用户自定义和系统内部定义(控件或应用程序提供 如Form1.WindowState = vbMinmized(窗口最小化vbMinmized就是系统内部提供的符号常量))
用户自定义 Const 符号常量名 [As 数据类型]=表达式
就拿你上面的圆周率来说选择用户自定义
Const PI =3.14159
这样就可以调用 PI 了
看看我写的代码更有利于你理解:
Option Explicit
Const PI = 3.14159
Private Sub Command1_Click()
Dim r As Single
Dim s As Single
r = Val(InputBox("请输入半径:"))
s = PI * r * r
Print s
End Sub呵呵。希望能帮到你,觉得不好欢迎批评建议!虚心学习......
vb.net 计算圆周率公式Private Sub Button2_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button2.Click
Dim s As Double
Dim n As Integer
s = 2
For n = 1 To 10000
s = s * (2 * n) ^ 2 / (2 * n - 1) / (2 * n1)
Next n
MsgBox("圆周率π的值是"s)
End Sub
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