随机矩阵vb.net 随机矩阵特征值小于等于1

用vb.net编程,建立一个m行n列的矩阵,找出其中最小的元素所在的行和列,并输出该值及其行、列位置没错!!
你的算法是:
1.定义三个变量,minValue(放最小值),X(放最小值的X坐标),Y(放最小值的Y坐标) 。
2.遍历矩阵 。在遍历过程中将最小值放在minValue中 , 最小值的X坐标放在X中,最小值的Y坐标放在X中 。
vb中利用随机数生成一个3×4的矩阵,数据的范围为20~70, 要求结果在窗体上输出.麻烦给我代码,谢谢~private sub form_click()
cls
dim i as integer,j as integer
【随机矩阵vb.net 随机矩阵特征值小于等于1】dim a(3,4) as integer
randomize
for i=1 to 3
for j=1 to 4
a(i,j)=int(rnd*51 20)
next
next
print "随机产生的3*4矩阵:"
for i=1 to 3
for i=1 to 4
print a(i,j);
next
print
next
end sub
有什么问题请留言 。
VB 数组随机排列方法很多随机矩阵vb.net , 在窗体上添加一个按钮 , 两个标签,见下图:
窗体随机矩阵vb.net的AutoRedraw 属性修改为True,两个标签随机矩阵vb.net的AutoSize 属性修都改为True 。
启动后见下图:
单击按钮先下图:
完整代码如下:
Option Explicit
Private d(7, 5) As Integer
Private a(35) As Integer
Private Sub Command1_Click()
Dim i As Integer
Dim j As Integer
Dim n As Integer
'生成1-35随机序列存入数组A
n = 0
Randomize
Do While n35
j = Int(Rnd * 351)
For i = 1 To n
If j = a(i) Then Exit For
Next i
If in Then
n = n1
a(n) = j
End If
Loop
'按照数组A系列重新给数组D赋值
n = 0
For i = 1 To 7
For j = 1 To 5
n = n1
d(i, j) = a(n)
Next j
Next i
'在标签2里显示
Label2.Caption = ""vbCrLf
For i = 1 To 7
For j = 1 To 5
Label2.Caption = Label2.CaptionRight(""CStr(d(i, j)), 4)
Next j
Label2.Caption = Label2.CaptionvbCrLf
Next i
End Sub
Private Sub Form_Load()
Dim i As Integer
Dim j As Integer
Dim n As Integer
'数组D初始化
n = 0
For i = 1 To 7
For j = 1 To 5
n = n1
d(i, j) = n
Next j
Next i
'在标签1里显示
Label1.Caption = ""vbCrLf
For i = 1 To 7
For j = 1 To 5
Label1.Caption = Label1.CaptionRight(""CStr(d(i, j)), 4)
Next j
Label1.Caption = Label1.CaptionvbCrLf
Next i
End Sub
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