Dijkstra（使用STL的priority_queue的最短路径算法） _priority_queue

给定一个图和图中的一个源顶点, 找到从源到给定图中所有顶点的最短路径。

Input : Source = 0Output : VertexDistance from Source00142123194215116978814

我们已经讨论了Dijkstra最短Path的实现。

Dijkstra的邻接矩阵表示算法(在C / C ++中, 时间复杂度为O(v2)
Dijkstra的邻接表表示算法(时间复杂度为O(ELogV)的C语言)
Dijkstra使用STL中设置的最短路径算法(在C ++中具有时间复杂度O(ELogV))

第二种实现方式是时间复杂度更好, 但由于我们实现了自己的优先级队列, 因此确实很复杂。
第三种实现更简单, 因为它使用STL。第三个实现的问题是, 它使用set, 而set又使用了Self-Balancing Binary Search Trees。对于Dijkstra的算法, 总是建议使用堆(或优先级队列), 因为所需的操作(提取最小和减小键)要与堆(或优先级队列)的特性相匹配。但是, 问题是, priority_queue不支持减小键。要解决此问题, 请不要更新密钥, 而要再插入一个副本。因此, 我们允许优先级队列中具有相同顶点的多个实例。这种方法不需要减少按键操作, 并且具有以下重要属性。

每当顶点距离减小时, 我们就会在priority_queue中添加一个顶点实例。即使存在多个实例, 我们也只考虑最小距离的实例, 而忽略其他实例。
时间复杂度保持为O(ELogV)), 因为优先级队列中最多会有O(E)个顶点, 并且O(Log E)与O(Log V)相同

下面是基于以上思想的算法。

1) Initialize distances of all vertices as infinite.2) Create an empty priority_queue pq.Every itemof pq is a pair (weight, vertex). Weight (or distance) is used used as first itemof pairas first item is by default used to comparetwo pairs3) Insert source vertex into pq and make itsdistance as 0.4) While either pq doesn't become emptya) Extract minimum distance vertex from pq. Let the extracted vertex be u.b) Loop through all adjacent of u and do following for every vertex v.// If there is a shorter path to v// through u. If dist[v] > dist[u] + weight(u, v)(i) Update distance of v, i.e., dodist[v] = dist[u] + weight(u, v)(ii) Insert v into the pq (Even if v isalready there)5) Print distance array dist[] to print all shortestpaths.

以下是上述想法的C ++实现。

// Program to find Dijkstra's shortest path using // priority_queue in STL #include< bits/stdc++.h> using namespace std; # define INF 0x3f3f3f3f// iPair ==> Integer Pair typedef pair< int , int > iPair; // This class represents a directed graph using // adjacency list representation class Graph { int V; // No. of vertices// In a weighted graph, we need to store vertex // and weight pair for every edge list< pair< int , int > > *adj; public : Graph( int V); // Constructor// function to add an edge to graph void addEdge( int u, int v, int w); // prints shortest path from s void shortestPath( int s); }; // Allocates memory for adjacency list Graph::Graph( int V) { this -> V = V; adj = new list< iPair> [V]; }void Graph::addEdge( int u, int v, int w) { adj[u].push_back(make_pair(v, w)); adj[v].push_back(make_pair(u, w)); }// Prints shortest paths from src to all other vertices void Graph::shortestPath( int src) { // Create a priority queue to store vertices that // are being preprocessed. This is weird syntax in C++. // Refer below link for details of this syntax // https://www.lsbin.org/implement-min-heap-using-stl/ priority_queue< iPair, vector < iPair> , greater< iPair> > pq; // Create a vector for distances and initialize all // distances as infinite (INF) vector< int > dist(V, INF); // Insert source itself in priority queue and initialize // its distance as 0. pq.push(make_pair(0, src)); dist[src] = 0; /* Looping till priority queue becomes empty (or all distances are not finalized) */ while (!pq.empty()) { // The first vertex in pair is the minimum distance // vertex, extract it from priority queue. // vertex label is stored in second of pair (it // has to be done this way to keep the vertices // sorted distance (distance must be first item // in pair) int u = pq.top().second; pq.pop(); // 'i' is used to get all adjacent vertices of a vertex list< pair< int , int > > ::iterator i; for (i = adj[u].begin(); i != adj[u].end(); ++i) { // Get vertex label and weight of current adjacent // of u. int v = (*i).first; int weight = (*i).second; //If there is shorted path to v through u. if (dist[v] > dist[u] + weight) { // Updating distance of v dist[v] = dist[u] + weight; pq.push(make_pair(dist[v], v)); } } }// Print shortest distances stored in dist[] printf ( "VertexDistance from Source\n" ); for ( int i = 0; i < V; ++i) printf ( "%d \t\t %d\n" , i, dist[i]); }// Driver program to test methods of graph class int main() { // create the graph given in above fugure int V = 9; Graph g(V); //making above shown graph g.addEdge(0, 1, 4); g.addEdge(0, 7, 8); g.addEdge(1, 2, 8); g.addEdge(1, 7, 11); g.addEdge(2, 3, 7); g.addEdge(2, 8, 2); g.addEdge(2, 5, 4); g.addEdge(3, 4, 9); g.addEdge(3, 5, 14); g.addEdge(4, 5, 10); g.addEdge(5, 6, 2); g.addEdge(6, 7, 1); g.addEdge(6, 8, 6); g.addEdge(7, 8, 7); g.shortestPath(0); return 0; }

输出如下：

VertexDistance from Source00142123194215116978814

使用更快的实现加权图的对表示向量:

// Program to find Dijkstra's shortest path using // priority_queue in STL #include< bits/stdc++.h> using namespace std; # define INF 0x3f3f3f3f// iPair ==> Integer Pair typedef pair< int , int > iPair; // To add an edge void addEdge(vector < pair< int , int > > adj[], int u, int v, int wt) { adj[u].push_back(make_pair(v, wt)); adj[v].push_back(make_pair(u, wt)); }// Prints shortest paths from src to all other vertices void shortestPath(vector< pair< int , int > > adj[], int V, int src) { // Create a priority queue to store vertices that // are being preprocessed. This is weird syntax in C++. // Refer below link for details of this syntax // http://geeksquiz.com/implement-min-heap-using-stl/ priority_queue< iPair, vector < iPair> , greater< iPair> > pq; // Create a vector for distances and initialize all // distances as infinite (INF) vector< int > dist(V, INF); // Insert source itself in priority queue and initialize // its distance as 0. pq.push(make_pair(0, src)); dist[src] = 0; /* Looping till priority queue becomes empty (or all distances are not finalized) */ while (!pq.empty()) { // The first vertex in pair is the minimum distance // vertex, extract it from priority queue. // vertex label is stored in second of pair (it // has to be done this way to keep the vertices // sorted distance (distance must be first item // in pair) int u = pq.top().second; pq.pop(); // Get all adjacent of u. for ( auto x : adj[u]) { // Get vertex label and weight of current adjacent // of u. int v = x.first; int weight = x.second; // If there is shorted path to v through u. if (dist[v] > dist[u] + weight) { // Updating distance of v dist[v] = dist[u] + weight; pq.push(make_pair(dist[v], v)); } } }// Print shortest distances stored in dist[] printf ( "Vertex Distance from Source\n" ); for ( int i = 0; i < V; ++i) printf ( "%d \t\t %d\n" , i, dist[i]); }// Driver program to test methods of graph class int main() { int V = 9; vector< iPair > adj[V]; // making above shown graph addEdge(adj, 0, 1, 4); addEdge(adj, 0, 7, 8); addEdge(adj, 1, 2, 8); addEdge(adj, 1, 7, 11); addEdge(adj, 2, 3, 7); addEdge(adj, 2, 8, 2); addEdge(adj, 2, 5, 4); addEdge(adj, 3, 4, 9); addEdge(adj, 3, 5, 14); addEdge(adj, 4, 5, 10); addEdge(adj, 5, 6, 2); addEdge(adj, 6, 7, 1); addEdge(adj, 6, 8, 6); addEdge(adj, 7, 8, 7); shortestPath(adj, V, 0); return 0; }

输出如下：

Vertex Distance from Source00142123194215116978814

进一步优化
我们可以使用一个标志数组来存储从优先级队列中提取的所有顶点。这样, 我们可以避免更新已提取项目的权重。请参阅
这个
优化的实现。
【Dijkstra（使用STL的priority_queue的最短路径算法）】本文作者：Shubham Agrawal。如果发现任何不正确的地方, 或者想分享有关上述主题的更多信息, 请发表评论。