JPA连接策略

在联合策略中, 将为每个实体类生成一个单独的表。每个表的属性都与主键结合在一起。它消除了重复的可能性。
以下语法代表了连接的策略:-

@Inheritance(strategy=InheritanceType.JOINED)

连接策略实例 在此示例中, 我们将员工分为在职员工和退休员工。
因此, 子类ActiveEmployees和RetiredEmployees继承父类Employee的e_id和e_name字段。
现在, 按照以下步骤创建JPA项目:-
  • 在com.srcmini.jpa.inheritence包下创建一个根实体类Employee.java, 并指定所有必需的变量和注释。
Employee.java
package com.srcmini.jpa.inheritence; import java.io.Serializable; import javax.persistence.*; @Entity@Table(name="employee_details")@Inheritance(strategy=InheritanceType.JOINED)public class Employee implements Serializable { @Idprivate int e_id; private String e_name; public Employee(int e_id, String e_name) { super(); this.e_id = e_id; this.e_name = e_name; }public Employee() { super(); }public int getE_id() { return e_id; }public void setE_id(int e_id) { this.e_id = e_id; }public String getE_name() { return e_name; }public void setE_name(String e_name) { this.e_name = e_name; }}

  • 在com.srcmini.jpa.inheritence包下创建一个实体类ActiveEmployee.java(Employee.java的子类)。
ActiveEmployee.java
package com.srcmini.jpa.inheritence; import javax.persistence.*; @Entitypublic class ActiveEmployee extends Employee { private int e_salary; private int e_experience; public ActiveEmployee(int e_id, String e_name, int e_salary, int e_experience) {super(e_id, e_name); this.e_salary = e_salary; this.e_experience = e_experience; } public ActiveEmployee() {super(); } public int getE_salary() {return e_salary; } public void setE_salary(int e_salary) {this.e_salary = e_salary; } public int getE_experience() {return e_experience; } public void setE_experience(int e_experience) {this.e_experience = e_experience; } }

  • 在com.srcmini.jpa.inheritence包下创建另一个实体类RetiredEmployee.java(Employee.java的子类)。
RetiredEmployee.java
package com.srcmini.jpa.inheritence; import javax.persistence.*; @Entitypublic class RetiredEmployee extends Employee { private int e_pension; public RetiredEmployee(int e_id, String e_name, int e_pension) {super(e_id, e_name); this.e_pension = e_pension; } public RetiredEmployee() {super(); } public int getE_pension() {return e_pension; } public void setE_pension(int e_pension) {this.e_pension = e_pension; } }

  • 现在, 在Persistence.xml文件中映射实体类和其他数据库配置。
Persistence.xml
< persistence> < persistence-unit name="Employee_details"> < class> com.srcmini.jpa.inheritence.ActiveEmployee< /class> < class> com.srcmini.jpa.inheritence.RetiredEmployee< /class> < class> com.srcmini.jpa.inheritence.Employee< /class> < properties> < property name="javax.persistence.jdbc.driver" value="http://www.srcmini.com/com.mysql.jdbc.Driver"/> < property name="javax.persistence.jdbc.url" value="http://www.srcmini.com/jdbc:mysql://localhost:3306/employee"/> < property name="javax.persistence.jdbc.user" value="http://www.srcmini.com/root"/> < property name="javax.persistence.jdbc.password" value=""/> < property name="eclipselink.logging.level" value="http://www.srcmini.com/SEVERE"/> < property name="eclipselink.ddl-generation" value="http://www.srcmini.com/create-or-extend-tables"/> < /properties> < /persistence-unit> < /persistence>

  • 在com.srcmini.jpa.persistence包下创建一个持久性类EmployeePersistence.java。此类用于初始化对象并将其持久化。
EmployeePersistence.java
package com.srcmini.jpa.persistence; import javax.persistence.*; import com.srcmini.jpa.inheritence.*; public class EmployeePersistence { public static void main(String[] args) { EntityManagerFactory emf=Persistence.createEntityManagerFactory("Employee_details"); EntityManager em=emf.createEntityManager(); em.getTransaction().begin(); ActiveEmployee ae1=new ActiveEmployee(101, "Karun", 10000, 5); ActiveEmployee ae2=new ActiveEmployee(102, "Rishab", 12000, 7); RetiredEmployee re1=new RetiredEmployee(103, "Ramesh", 5000); RetiredEmployee re2=new RetiredEmployee(104, "Raj", 4000); em.persist(ae1); em.persist(ae2); em.persist(re1); em.persist(re2); em.getTransaction().commit(); em.close(); emf.close(); }}

程序执行后, 以下目录层次结构在MySQL工作台下生成。
JPA连接策略

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输出:
【JPA连接策略】现在, 分别从每个表中获取数据以生成输出。
  • 从employee_details中选择*
JPA连接策略

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  • 选择* from active_employee
JPA连接策略

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  • 选择* from退休员工
JPA连接策略

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