C语言实现发牌洗牌 C语言实现发牌洗牌

本文实例为大家分享了C语言实现发牌洗牌的具体代码，供大家参考，具体内容如下
1.模拟发牌程序
通过写两个函数模块来编写洗牌程序和打印的发牌程序
2.编写洗牌程序

void shuffle(char cards[][10],int n){int i=54; char ca,cb,ct[10]; srand((unsigned)time(NULL)); while(i--){ca=rand()%54; cb=rand()%54; strcpy(ct,cards[ca]); strcpy(cards[ca],cards[cb]); strcpy(cards[cb],ct); }}

3.编写打印的发牌程序

void printCard(char cards[][10],int n){int i,rn=0; printf("第一个人:\n"); for(i=0; i<17; i++){if(rn%5==0)printf("\n"); rn++; printf("%s",cards[i]); }printf("\n\n第二个人:\n"); rn=0; for(i=17; i<33; i++){if(rn%5==0)printf("\n"); rn++; printf("%s",cards[i]); }printf("\n\n第三个人:\n"); rn=0; for(i=33; i<50; i++){if(rn%5==0)printf("\n"); rn++; printf("%s",cards[i]); }printf("\n\n底牌:\n"); for(i=51; i<54; i++){printf("%s",cards[i]); }printf("\n"); getchar(); }

4.在主函数预定义和调用

main(){system("color 0f"); char cards[][10]={"红桃 2","红桃 3","红桃 4","红桃 5","红桃 6","红桃 7","红桃 8","红桃 9","红桃 10","红桃 J","红桃 Q","红桃 K","红桃 A","方块 2","方块 3","方块 4","方块 5","方块 6","方块 7","方块 8","方块 9","方块 10","方块 J","方块 Q","方块 K","方块 A","梅花 2","梅花 3","梅花 4","梅花 5","梅花 6","梅花 7","梅花 8","梅花 9","梅花 10","梅花 J","梅花 Q","梅花 K","梅花 A","黑桃 2","黑桃 3","黑桃 4","黑桃 5","黑桃 6","黑桃 7","黑桃 8","黑桃 9","黑桃 10","黑桃 J","黑桃 Q","黑桃 K","黑桃 A","大王","小王" }; int n = 54; shuffle(cards,n); printCard( cards, n); return 0; }

5.最终程序

#include#include#include #includevoid shuffle(char cards[][10],int n); void printCard(char cards[][10],int n); main(){system("color 0f"); char cards[][10]={"红桃 2","红桃 3","红桃 4","红桃 5","红桃 6","红桃 7","红桃 8","红桃 9","红桃 10","红桃 J","红桃 Q","红桃 K","红桃 A","方块 2","方块 3","方块 4","方块 5","方块 6","方块 7","方块 8","方块 9","方块 10","方块 J","方块 Q","方块 K","方块 A","梅花 2","梅花 3","梅花 4","梅花 5","梅花 6","梅花 7","梅花 8","梅花 9","梅花 10","梅花 J","梅花 Q","梅花 K","梅花 A","黑桃 2","黑桃 3","黑桃 4","黑桃 5","黑桃 6","黑桃 7","黑桃 8","黑桃 9","黑桃 10","黑桃 J","黑桃 Q","黑桃 K","黑桃 A","大王","小王" }; int n = 54; shuffle(cards,n); printCard( cards, n); return 0; }void shuffle(char cards[][10],int n){int i=54; char ca,cb,ct[10]; srand((unsigned)time(NULL)); while(i--){ca=rand()%54; cb=rand()%54; strcpy(ct,cards[ca]); strcpy(cards[ca],cards[cb]); strcpy(cards[cb],ct); }}void printCard(char cards[][10],int n){int i,rn=0; printf("第一个人:\n"); for(i=0; i<17; i++){if(rn%5==0)printf("\n"); rn++; printf("%s",cards[i]); }printf("\n\n第二个人:\n"); rn=0; for(i=17; i<33; i++){if(rn%5==0)printf("\n"); rn++; printf("%s",cards[i]); }printf("\n\n第三个人:\n"); rn=0; for(i=33; i<50; i++){if(rn%5==0)printf("\n"); rn++; printf("%s",cards[i]); }printf("\n\n底牌:\n"); for(i=51; i<54; i++){printf("%s",cards[i]); }printf("\n"); getchar(); }

6.1程序结果