BasicNetwork.performRequest（意外响应代码401 android Volley库）

智慧并不产生于学历,而是来自对于知识的终生不懈的追求。这篇文章主要讲述BasicNetwork.performRequest：意外响应代码401 android Volley库相关的知识，希望能为你提供帮助。

我在android中调用web服务。因为我想调用URL我没有向服务器发送任何参数，只是调用URL，

但它的错误如[10520] BasicNetwork.performRequest：意外的响应代码401
【BasicNetwork.performRequest（意外响应代码401 android Volley库）】我的代码是

RequestQueue queue = Volley.newRequestQueue(getActivity()); JsonObjectRequest getRequest = new JsonObjectRequest(Request.Method.GET, Server.URL, null, new Response.Listener< JSONObject> () { @Override public void onResponse(JSONObject response) { // display response hideProgressDialog(); } }, new Response.ErrorListener() { @Override public void onErrorResponse(VolleyError error) { hideProgressDialog(); } } ); // add it to the RequestQueue queue.add(getRequest);

怎么解决这个？
答案此错误意味着您需要进行身份验证。您可以这样做，将getHeaders（）添加到您的代码中，所以它是这样的：

RequestQueue queue = Volley.newRequestQueue(getActivity()); JsonObjectRequest getRequest = new JsonObjectRequest(Request.Method.GET, Server.URL, null, new Response.Listener< JSONObject> () { @Override public void onResponse(JSONObject response) { // display response hideProgressDialog(); } }, new Response.ErrorListener() { @Override public void onErrorResponse(VolleyError error) { hideProgressDialog(); } }@Override public Map< String, String> getHeaders() throws AuthFailureError { HashMap< String, String> params = new HashMap< String, String> (); params.put("Content-Type", "application/json"); String creds = String.format("%s:%s","username","password"); String auth = "Basic " + Base64.encodeToString(creds.getBytes(), Base64.DEFAULT); params.put("Authorization", auth); return params; } ); queue.add(getRequest);

另一答案HTTP 401表示网站需要身份验证，但未提供或失败。您需要对自己进行身份验证。未知是否需要提供HTTP基本身份验证，或者Web服务是否需要特殊身份验证，并且只是对其返回值很聪明。
另一答案如果我们使用POST而不是GET或GET而不是POST勒芒，则会发生此错误
所以，在这一行中将GET改为Post

JsonObjectRequest getRequest = new JsonObjectRequest(Request.Method.GET, Server.URL, null, new Response.Listener< JSONObject> ()

另一答案

String http_post() {RequestQueue MyRequestQueue = Volley.newRequestQueue(Library.this); //String url = "http://" + "hqplayer" + ":" + Utils.password + "@" + Utils.ip + ":8088/library"; String url = "http://" + Utils.ip + ":8088/library"; Log.i(TAG, "HttpPost() < " + url + "> "); String credentials = "hqplayer:valvole"; byte[] t = credentials.getBytes(); byte[] auth = Base64.encode(t, Base64.DEFAULT); final String basicAuthValue = https://www.songbingjia.com/android/new String(auth); MyRequestQueue.add(new StringRequest(Request.Method.POST, url, new Response.Listener< String> () { @Override public void onResponse(String response) { Log.i(TAG,"HttpPost() - onResponse() "); } }, new Response.ErrorListener() { @Override public void onErrorResponse(VolleyError error) { Log.i(TAG, "HttpPost() - onErrorResponse() "); Log.i(TAG, "HttpPost() error < " + error + "> "); } }) { @Override public Map< String, String> getHeaders() throws AuthFailureError { HashMap< String, String> params = new HashMap< String, String> (); String creds = String.format("%s:%s","hqplayer","valvole"); String auth = "Basic " + Base64.encodeToString(creds.getBytes(), Base64.DEFAULT); params.put("Authorization", auth); return params; }}); return null; }

另一答案添加getHeader

@Override public Map< String, String> getHeaders() throws AuthFailureError { HashMap< String, String> headers = new HashMap< String, String> (); headers.put("token", SharedVariables.TOKEN); headers.put("device", SharedVariables.DEVICE_ID); headers.put("accept-language", "en-US"); headers.put("api-version", "1.0"); return headers; }

另一答案添加标题...也许您忘记在排球请求中添加标题。