SpringMvc接受请求参数的几种情况演示 SpringMvc接受请求参数的几种情

说明：
通常get请求获取的参数是在url后面，而post请求获取的是请求体当中的参数。因此两者在请求方式上会有所不同。
1.直接将接受的参数写在controller对应方法的形参当中（适用于get提交方式）

/*** 1.直接把表单的参数写在Controller相应的方法的形参中** @param username* @param password* @return*/@GetMapping("/addUser1")public String addUser1(String username, String password) {System.out.println ("username is:" + username); System.out.println ("password is:" + password); return username + "," + password; }

2.通过url请求路径获取参数

/*** 2、通过@PathVariable获取路径中的参数** @param username* @param password* @return*/@RequestMapping(value = "https://www.it610.com/addUser4/{username}/{password}", method = RequestMethod.GET)public String addUser4(@PathVariable String username, @PathVariable String password) {System.out.println ("username is:" + username); System.out.println ("password is:" + password); return "addUser4"; }

3.通过request请求对象来接受发来的参数信息（Get请求方式或者时Post请求方式都可以）

/*** 3、通过HttpServletRequest接收** @param request* @return*/@RequestMapping("/addUser2")public String addUser2(HttpServletRequest request) {String username = request.getParameter ("username"); String password = request.getParameter ("password"); System.out.println ("username is:" + username); System.out.println ("password is:" + password); return "demo/index"; }

4.封装JavaBean对象的方式来接受请求参数（get方式与post方式都可以）
4.1首先在模块当中创建对应的JavaBean,并提供相应的get,set方法。

package com.example.demo.pojo; import lombok.Data; @Datapublic class User1 {private String username; private String password; }

4.2Controller层

/*** 4、通过一个bean来接收** @param user* @return*/@RequestMapping("/addUser3")public String addUser3(User1 user) {System.out.println ("username is:" + user.getUsername ( )); System.out.println ("password is:" + user.getPassword ( )); return "/addUser3"; }

5.使用注解@RequestParam注解将请求参数绑定到Controller层对应方法的形参当中

/*** 5、用注解@RequestParam绑定请求参数到方法入参* @param username* @param password* @return*/@RequestMapping(value="https://www.it610.com/addUser6",method=RequestMethod.GET)public String addUser6(@RequestParam("username") String username,@RequestParam("password") String password) {System.out.println("username is:"+username); System.out.println("password is:"+password); return "demo/index"; }

下面介绍，发送json格式的请求，接受数据的情况：
1.将json请求的key,value值封装到实体对象的属性当中（通常将参数放在请求体body中，以application/json格式被后端获取）
1.1创建一个实体类

public class User2 implements Serializable {private static final long serialVersionUID = 1L; @JsonProperty(value = "https://www.it610.com/article/id")private Integer id; @JsonProperty(value = "https://www.it610.com/article/name")private String name; @JsonProperty(value = "https://www.it610.com/article/age")private Integer age; @JsonProperty(value = "https://www.it610.com/article/hobby")private List hobby;

/***将json请求的key,value封装到实体对象当中。* @param user* @return*/@PostMapping("/save")public String saveUser(@RequestBody User2 user) {//list.add(user); //User2 user2 = new User2 (); //user2.setId (user.getId ()); //user2.setAge (user.getAge ()); //user2.setName (user.getName ()); //user2.setHobby (user.getHobby ()); return "success"+user; }

2.将json请求的key，value值封装到request对象的属性当中（通常请求参数放body中，将content-type改为x-www-form-urlencoded）

/*** 将请求参数封装到request对象当中。* @param request* @return*/@PostMapping("/save2")public User2 save(HttpServletRequest request) {Integer id = Integer.parseInt(request.getParameter("id")); String name = request.getParameter("name"); Integer age = Integer.parseInt(request.getParameter("age")); String parameter = request.getParameter("hobby"); List stringList = new ArrayList<> (); String[] split = parameter.split (","); for (int i = split.length - 1; i >= 0; i--) {stringList.add (split[i]); }User2 user2 = new User2(id, name, age, stringList); //list.add(user); return user2; }

3.通过http协议，将json参数转成JSONOBject对象
【SpringMvc接受请求参数的几种情况演示】3.1Controller层接受JSON参数

/*** 通过http协议将参数转为jsonobject* @param request* @return* @throws IOException* @throws JSONException*/@PostMapping("/save3")public User2 save3(HttpServletRequest request) throws IOException, JSONException {JSONObject jsonObject = handlerData(request); Integer id = jsonObject.getInteger("id"); String name = jsonObject.getString("name"); Integer age = jsonObject.getInteger("age"); List hobby = jsonObject.getObject("hobby", List.class); User2 user3 = new User2 (id, name, age, hobby); //list.add(user); return user3; }

3.2通过以下方法将Json字符串转成Jsonobject对象

//这里使用的是alibaba的json工具类public static JSONObject handlerData(HttpServletRequest request) throws IOException, JSONException {StringBuffer sb = new StringBuffer(); InputStream is = request.getInputStream(); BufferedReader br = new BufferedReader(new InputStreamReader (is, "utf-8")); String s = ""; while ((s = br.readLine()) != null) {sb.append(s); }if (sb.toString().length() <= 0) {return null; } else {return JSONObject.parseObject(sb.toString()); }}

4.将json格式的请求参数封装到hashmap的key,value键-值对当中。（json字符串串放在body中，请求格式为application/json格式）

/***将json请求的Key,value封装到map的key,value当中去。* @param map* @return*/@PostMapping("/save1")public User2 saveUser1(@RequestBody Map map) {Integer id = (Integer) map.get("id"); String name = (String) map.get("name"); Integer age = (Integer) map.get("age"); List hobby=(List) map.get("hobby"); User2 user = new User2(id, name, age, hobby); //list.add(user); return user; }

该文档主要是学习以下两篇文档的总结：
https://www.cnblogs.com/lirenhe/p/10737673.html
https://blog.csdn.net/zyxwvuuvwxyz/article/details/80352712
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