使用c++实现OpenCV绘制圆端矩形使用c++实现OpenCV绘制圆端矩形

功能函数

// 绘制圆端矩形（药丸状，pill）void DrawPill(cv::Mat mask, const cv::RotatedRect &rotatedrect, const cv::Scalar &color, int thickness, int lineType){ cv::Mat canvas = cv::Mat::zeros(mask.size(), CV_8UC1); // 确定短边，短边绘制圆形 cv::RotatedRect rect = rotatedrect; float r = rect.size.height / 2.0f; if (rect.size.width > rect.size.height) {rect.size.width -= rect.size.height; } else {rect.size.height -= rect.size.width; r = rect.size.width / 2.0f; } cv::Point2f ps[4]; rect.points(ps); // 绘制边缘 std::vector> tmpContours; std::vector contours; for (int i = 0; i != 4; ++i) {contours.emplace_back(cv::Point2i(ps[i])); } tmpContours.insert(tmpContours.end(), contours); drawContours(canvas, tmpContours, 0, cv::Scalar(255),5, lineType); // 填充mask// 计算常长短轴 float a = rotatedrect.size.width; float b = rotatedrect.size.height; int point01_x = (int)((ps[0].x + ps[1].x) / 2.0f); int point01_y = (int)((ps[0].y + ps[1].y) / 2.0f); int point03_x = (int)((ps[0].x + ps[3].x) / 2.0f); int point03_y = (int)((ps[0].y + ps[3].y) / 2.0f); int point12_x = (int)((ps[1].x + ps[2].x) / 2.0f); int point12_y = (int)((ps[1].y + ps[2].y) / 2.0f); int point23_x = (int)((ps[2].x + ps[3].x) / 2.0f); int point23_y = (int)((ps[2].y + ps[3].y) / 2.0f); cv::Point c0 = a < b ? cv::Point(point12_x, point12_y) : cv::Point(point23_x, point23_y); cv::Point c1 = a < b ? cv::Point(point03_x, point03_y) : cv::Point(point01_x, point01_y); // 长轴两端以填充的方式画圆，直径等于短轴 cv::circle(canvas, c0, (int)r, cv::Scalar(255), 5, lineType); cv::circle(canvas, c1, (int)r, cv::Scalar(255), 5, lineType); // 绘制外围轮廓，如果不这样操作，会得到一个矩形加两个圆形，丑。。。 std::vector> EXcontours; cv::findContours(canvas,EXcontours,cv::RETR_EXTERNAL, CHAIN_APPROX_SIMPLE); drawContours(mask, EXcontours, 0, color, thickness,lineType); // 填充mask}

测试代码

#include #include using namespace std; using namespace cv; void DrawPill(cv::Mat mask, const cv::RotatedRect &rotatedrect, const cv::Scalar &color, int thickness, int lineType); int main(){ cv::Mat src = https://www.it610.com/article/imread("test.jpg"); cv::Mat result = src.clone(); cv::RotatedRect rorect(cv::Point(src.cols / 2, src.rows / 2), cv::Size(1000, 800), 50); DrawPill(result, rorect, cv::Scalar(0, 255, 255),8,16); imshow("original", src); imshow("result", result); waitKey(0); return 0; } // 绘制圆端矩形（药丸状，pill）void DrawPill(cv::Mat mask, const cv::RotatedRect &rotatedrect, const cv::Scalar &color, int thickness, int lineType){ cv::Mat canvas = cv::Mat::zeros(mask.size(), CV_8UC1); // 确定短边，短边绘制圆形 cv::RotatedRect rect = rotatedrect; float r = rect.size.height / 2.0f; if (rect.size.width > rect.size.height) {rect.size.width -= rect.size.height; } else {rect.size.height -= rect.size.width; r = rect.size.width / 2.0f; } cv::Point2f ps[4]; rect.points(ps); // 绘制边缘 std::vector> tmpContours; std::vector contours; for (int i = 0; i != 4; ++i) {contours.emplace_back(cv::Point2i(ps[i])); } tmpContours.insert(tmpContours.end(), contours); drawContours(canvas, tmpContours, 0, cv::Scalar(255),5, lineType); // 填充mask// 计算常长短轴 float a = rotatedrect.size.width; float b = rotatedrect.size.height; int point01_x = (int)((ps[0].x + ps[1].x) / 2.0f); int point01_y = (int)((ps[0].y + ps[1].y) / 2.0f); int point03_x = (int)((ps[0].x + ps[3].x) / 2.0f); int point03_y = (int)((ps[0].y + ps[3].y) / 2.0f); int point12_x = (int)((ps[1].x + ps[2].x) / 2.0f); int point12_y = (int)((ps[1].y + ps[2].y) / 2.0f); int point23_x = (int)((ps[2].x + ps[3].x) / 2.0f); int point23_y = (int)((ps[2].y + ps[3].y) / 2.0f); cv::Point c0 = a < b ? cv::Point(point12_x, point12_y) : cv::Point(point23_x, point23_y); cv::Point c1 = a < b ? cv::Point(point03_x, point03_y) : cv::Point(point01_x, point01_y); // 长轴两端以填充的方式画圆，直径等于短轴 cv::circle(canvas, c0, (int)r, cv::Scalar(255), 5, lineType); cv::circle(canvas, c1, (int)r, cv::Scalar(255), 5, lineType); // 绘制外围轮廓，如果不这样操作，会得到一个矩形加两个圆形，丑。。。 std::vector> EXcontours; cv::findContours(canvas,EXcontours,cv::RETR_EXTERNAL, CHAIN_APPROX_SIMPLE); drawContours(mask, EXcontours, 0, color, thickness,lineType); // 填充mask}

测试效果