Void func delay(_ time: TimeInterval。延迟执行。" />

延迟执行

let time: TimeInterval = 1.0
DispatchQueue.main.asyncAfter(deadline: DispatchTime.now() + time) {
//code
print("1 秒后输出")
}




以下来自喵神
import Foundation
typealias Task = (_ cancel : Bool)-> Void
func delay(_ time: TimeInterval, task:@escaping()->())->Task? {
func dispatch_later(block:@escaping()->()) {
let t = DispatchTime.now()+time
DispatchQueue.main.asyncAfter(deadline: t, execute: block)
}
var closure:(()->Void)? = task
var result:Task?
let delayedClosure:Task = { cancel in
if let internalClosure = closure {
if (cancel ==false) {
DispatchQueue.main.async(execute: internalClosure)
}
}
closure = nil
result=nil
}
result = delayedClosure
dispatch_later {
if let delayedClosure = result {
delayedClosure(false)
}
}
return result
}
func cancel(_ task: Task?) {
task?(true)
}
/*****使用*****/
//调用
delay(2) {
print("2 秒后输出")
}
//取消
let task = delay(5) {
print("拨打 110")
}
// 仔细想一想..// 还是取消为妙..
【延迟执行】cancel(task)

    推荐阅读