VB.NET用正则表达提取数字的问题!你把替换所有非数字为空字符串,改为替换所有非数字为空格,就可以把每组数字分开了.
完整的程序如下(改动的地方见注释)
Dim bbb As String
bbb = TextBox1.Text
Dim My_str As String = Regex.Replace(bbb, "[^0-9]", " ") '这里把替换所有非数字为空字符串,改为替换所有非数字为空格
MsgBox(My_str)
vb 十进制转换成 八进制 二进制原码 二进制补码 二进制反码 程序VB.NET控制台程序:
Module module3
Sub Main()
Dim i As Integer
Dim num As Integer = -35
Dim R As Integer = 8
Dim arr(33) As Integer
Dim len As Integer
arr = TransToR(num, R)
len = arr(0)
Console.Write(num" 转换成 "R" 进制后:"vbTab)
If (arr(1) = 1) Then
Console.Write("-")
End If
For i = len1 To 2 Step -1
Console.Write(arr(i))
Next
Console.WriteLine()
arr = TransToSourceCode(num)
Console.Write(num" 转换成32位二进制源码后:"vbTab)
Console.Write(arr(1))
For i = 32 To 2 Step -1
Console.Write(arr(i))
Next
Console.WriteLine()
arr = TransToReverseCode(num)
Console.Write(num" 转换成32位二进制反码后:"vbTab)
Console.Write(arr(1))
For i = 32 To 2 Step -1
Console.Write(arr(i))
Next
Console.WriteLine()
arr = TransToCompensatoryCode(num)
Console.Write(num" 转换成32位二进制补码后:"vbTab)
Console.Write(arr(1))
【vb.net取反 vbnet function 有返回值 举例】For i = 32 To 2 Step -1
Console.Write(arr(i))
Next
Console.WriteLine()
End Sub
'将十进制数num转换为R(2=R=9)进制数,结果存在arr数组中
'arr(0)存储长度, arr(1)存储符号位:1为负,0为正
Function TransToR(ByVal num As Integer, ByVal R As Integer) As Integer()
Dim arr(33) As Integer
arr(0) = 0'初始长度
'设置符号位
If (num0) Then
arr(1) = 1
Else
arr(1) = 0
End If
num = Math.Abs(num)
While num0
arr(0) = arr(0)1
arr(arr(0)1) = num Mod R
num \= R
End While
Return arr
End Function
'将十进制数num转换为二进制原码
Function TransToSourceCode(ByVal num As Integer) As Integer()
Dim arr(33) As Integer
Dim i As Integer
arr = TransToR(num, 2)
'高位补零
For i = arr(0)2 To 32
arr(i) = 0
Next
arr(0) = 32
Return arr
End Function
'将十进制数num转换为二进制反码
Function TransToReverseCode(ByVal num As Integer) As Integer()
Dim arr(33) As Integer
Dim i As Integer
arr = TransToSourceCode(num)
If num = 0 Then
Return arr
End If
'除符号位外各位取反
For i = 2 To 33
arr(i) = 1 - arr(i)
Next
Return arr
End Function
'将十进制数num转换为二进制补码
Function TransToCompensatoryCode(ByVal num As Integer) As Integer()
Dim arr(33) As Integer
Dim i As Integer
Dim c As Integer = 0'进位
arr = TransToReverseCode(num)
If num = 0 Then
Return arr
End If
'末尾加1
i = 2
arr(i)= 1
Do While True
arr(i) = carr(i)
c = arr(i) \ 2
arr(i) = arr(i) Mod 2
i= 1
If c1 Then
Exit Do
End If
Loop
Return arr
End Function
End Module
C语言转换为VB.NETOption Explicit On
Option Strict On
Imports System
Module Program
Sub Main()
Dim y,m,t As Integer
begin:
' 输入数据时一行一个
y=CInt(Console.ReadLine())
m=CInt(Console.ReadLine())
t=CInt(Console.ReadLine())
If y
200 Then
Console.WriteLine("ERROR")
goto begin
End If
pr(y,m,t)
Console.Write("Press any key to continue . . . ")
Console.ReadKey(True)
End Sub
Function pr(y As Integer,m As Integer,t As Integer) As Integer
Dim ye,[Me],i As Integer
ye=CInt((m t-2)/12 y)
[Me]=(m t-2) Mod 12 1
End If
End Function
Function mday(y As Integer,m As Integer) As Integer
Dim day As Integer()={0,31,28,31,30,31,30,31,31,30,31,30,31}
Dim ad As I
vb中怎样对一个变量进行取反?vb中的变量取反是:not 变量
not,and,or,Xor 用做boolean值时,它们就作为逻辑运算符
not,and,or,Xor 用整数值时,它们就作为位运算符
例子:dim a as integer =not 143 'a=-144按位取反!~~~~~
Vb.net中如何判断字段为空?。。?/h2>if myreader.getstring(2)"" then
else
....
end if
取反 这样可以vb.net取反的 vb.net取反我一直就这样写
C# 如何使用 VB.net 中的Not?C#.NET和VB.NET是同一托管平台(framework)下的两种不同语言,当然语法会存在差异 。所以C#中无法写出以上代码 , 只能如此:
ButView.Check = false;
vb.net取反的介绍就聊到这里吧,感谢你花时间阅读本站内容 , 更多关于vbnet function 有返回值 举例、vb.net取反的信息别忘了在本站进行查找喔 。
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