c语言分段函数解题技巧 c语言分段函数的计算

c语言求分段函数帮c语言分段函数解题技巧你改了下代码c语言分段函数解题技巧,VC6测试通过c语言分段函数解题技巧,自己看看吧 。
#includestdio.h
int main()
{
float x,y;//根据给定c语言分段函数解题技巧的测试用例,x , y应该为float型
scanf("%f",x);//x为float型,所以改为%f
if(x20)
{
y=x 100;
}
else if(x=20x=100)
{
y=x;
}
else
y=x-100;
printf("x=%f,y=%f\n",x,y);
return 0;//缺少分号
}
怎么用c语言编程一个分段函数?#include
int main()
{
【c语言分段函数解题技巧 c语言分段函数的计算】int x,y;
scanf("%d",x);
if(0xx10) y=3*x 2;
else
{if(x=0) y=0;
else
{if (x0) y=x*x;
else printf("go die\n");
}
}
printf("%d",y);
return 0;
}该程序c语言分段函数解题技巧的分段函数如下:
f(x)=3x 2(0x10)
f(x)=1(x=0)
f(x) = x*x(x0)
#include stdio.h
#include math.h
void main()
{
float x;
double y;
printf("Please input the value of x:");
scanf("%f",x);
if(x=-10x=4)
{
y=fabs(x-2);
printf("y=%.2f\n",y);
}
else if(x=5x=7)
{
y=x 10;
printf("y=%.2f\n",y);
}
else if(x=8x=12)
{
y=pow(x,4);
printf("y=%.2f\n",y);
}
else
printf("No answer\n");
}
C语言计算分段函数1. 代码如下,3)需要实际运行时输入测试
int main(void)
{
double x, y, f;
printf("Please input 2 double number in the form of x y:\n");
scanf("%lf%lf", x, y);
if(x=0y0)
f = 2*x*x3*x1/(x y);
else if(x=0y=0)
f = 2*x*x3*x1/(1 y*y);
else
f = 3*sin(x y)/(2*x*x)3*x1;
printf("x=%lf, y=%lf, f(x, y)=%lf\n", x, y, f);
return 0;
}
2.代码如下
#include stdio.h
#includemath.h
int main(void)
{
double x, y, f;
printf("Please input 2 double number in the form of x y:\n");
scanf("%lf%lf", x, y);
if(x=0)
{
if(y0)
f = 2*x*x3*x1/(x y);
else
f = 2*x*x3*x1/(1 y*y);
}
else
f = 3*sin(x y)/(2*x*x)3*x1;
printf("x=%lf, y=%lf, f(x, y)=%lf\n", x, y, f);
return 0;
}
3.代码如下
#include stdio.h
int main(void)
{
int score = 0;
printf("Please input a score between 0-100:\n");
scanf("%d", score);
if(score0 || score100)
printf("Wrong input of score!\n");
else if(score=90score=100)
printf("A\n");
else if(score=80score=89)
printf("B\n");
else if(score=70score=79)
printf("C\n");
else if(score=60score=69)
printf("D\n");
else
printf("E\n");
return 0;
}
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