本文概述
- C ++
- C
- Java
- python
- C#
- 的PHP
范例:
Input :arr[] = [1, 2, 3, 4, 5, 6, 7]
d = 2
Output : arr[] = [3, 4, 5, 6, 7, 1, 2]
文章图片
将上面的数组旋转2将使数组
文章图片
推荐:请在"
实践
首先, 在继续解决方案之前。
在d中讨论了通过d个元素旋转数组的前3种方法。
这个
发布。
方法4(逆向算法):
算法:
rotate(arr[], d, n)
reverse(arr[], 1, d) ;
reverse(arr[], d + 1, n);
reverse(arr[], 1, n);
令AB为输入数组的两个部分, 其中A = arr [0..d-1]和B = arr [d..n-1]。该算法的思想是:
- 反转A以获得ArB, 其中Ar反转A。
- 反转B以获得ArBr, 其中Br是B的反转。
- 取反得到(ArBr)r = BA。
令数组为arr [] = [1、2、3、4、5、6、7], d = 2和n = 7
A = [1, 2]和B = [3, 4, 5, 6, 7]
- 反向A, 我们得到ArB = [2、1、3、4、5、6、7]
- 反向B, 我们得到ArBr = [2, 1, 7, 6, 6, 5, 4, 3]
- 颠倒全部, 我们得到(ArBr)r = [3, 4, 5, 5, 6, 7, 1, 2]
C ++
// C++ program for reversal algorithm
// of array rotation
#include <
bits/stdc++.h>
using namespace std;
/*Function to reverse arr[] from index start to end*/
void reverseArray( int arr[], int start, int end)
{
while (start <
end) {
int temp = arr[start];
arr[start] = arr[end];
arr[end] = temp;
start++;
end--;
}
}
/* Function to left rotate arr[] of size n by d */
void leftRotate( int arr[], int d, int n)
{
if (d == 0)
return ;
// in case the rotating factor is
// greater than array length
d = d % n;
reverseArray(arr, 0, d - 1);
reverseArray(arr, d, n - 1);
reverseArray(arr, 0, n - 1);
}
// Function to print an array
void printArray( int arr[], int size)
{
for ( int i = 0;
i <
size;
i++)
cout <
<
arr[i] <
<
" " ;
}
/* Driver program to test above functions */
int main()
{
int arr[] = { 1, 2, 3, 4, 5, 6, 7 };
int n = sizeof (arr) / sizeof (arr[0]);
int d = 2;
// Function calling
leftRotate(arr, d, n);
printArray(arr, n);
return 0;
}
C
// C/C++ program for reversal algorithm of array rotation
#include <
stdio.h>
/*Utility function to print an array */
void printArray( int arr[], int size);
/* Utility function to reverse arr[] from start to end */
void reverseArray( int arr[], int start, int end);
/* Function to left rotate arr[] of size n by d */
void leftRotate( int arr[], int d, int n)
{
if (d == 0)
return ;
// in case the rotating factor is
// greater than array length
d = d % n;
reverseArray(arr, 0, d - 1);
reverseArray(arr, d, n - 1);
reverseArray(arr, 0, n - 1);
}
/*UTILITY FUNCTIONS*/
/* function to print an array */
void printArray( int arr[], int size)
{
int i;
for (i = 0;
i <
size;
i++)
printf ( "%d " , arr[i]);
}
/*Function to reverse arr[] from index start to end*/
void reverseArray( int arr[], int start, int end)
{
int temp;
while (start <
end) {
temp = arr[start];
arr[start] = arr[end];
arr[end] = temp;
start++;
end--;
}
}
/* Driver program to test above functions */
int main()
{
int arr[] = { 1, 2, 3, 4, 5, 6, 7 };
int n = sizeof (arr) / sizeof (arr[0]);
int d = 2;
leftRotate(arr, d, n);
printArray(arr, n);
return 0;
}
Java
// Java program for reversal algorithm of array rotation
import java.io.*;
class LeftRotate {
/* Function to left rotate arr[] of size n by d */
static void leftRotate( int arr[], int d)
{
if (d == 0 )
return ;
int n = arr.length;
// in case the rotating factor is
// greater than array length
d = d % n;
reverseArray(arr, 0 , d - 1 );
reverseArray(arr, d, n - 1 );
reverseArray(arr, 0 , n - 1 );
}
/*Function to reverse arr[] from index start to end*/
static void reverseArray( int arr[], int start, int end)
{
int temp;
while (start <
end) {
temp = arr[start];
arr[start] = arr[end];
arr[end] = temp;
start++;
end--;
}
}
/*UTILITY FUNCTIONS*/
/* function to print an array */
static void printArray( int arr[])
{
for ( int i = 0 ;
i <
arr.length;
i++)
System.out.print(arr[i] + " " );
}
/* Driver program to test above functions */
public static void main(String[] args)
{
int arr[] = { 1 , 2 , 3 , 4 , 5 , 6 , 7 };
int n = arr.length;
int d = 2 ;
leftRotate(arr, d);
// Rotate array by d
printArray(arr);
}
}
/*This code is contributed by Devesh Agrawal*/
python
# Python program for reversal algorithm of array rotation
# Function to reverse arr[] from index start to end
def reverseArray(arr, start, end):
while (start <
end):
temp = arr[start]
arr[start] = arr[end]
arr[end] = temp
start + = 1
end = end - 1
# Function to left rotate arr[] of size n by d
def leftRotate(arr, d):
if d = = 0 :
return
n = len (arr)
# in case the rotating factor is
# greater than array length
d = d % n
reverseArray(arr, 0 , d - 1 )
reverseArray(arr, d, n - 1 )
reverseArray(arr, 0 , n - 1 )
# Function to print an array
def printArray(arr):
for i in range ( 0 , len (arr)):
print arr[i], # Driver function to test above functions
arr = [ 1 , 2 , 3 , 4 , 5 , 6 , 7 ]
n = len (arr)
d = 2
leftRotate(arr, d)# Rotate array by 2
printArray(arr)
# This code is contributed by Devesh Agrawal
C#
// C# program for reversal algorithm
// of array rotation
using System;
class GFG {
/* Function to left rotate arr[]
of size n by d */
static void leftRotate( int [] arr, int d)
{
if (d == 0)
return ;
int n = arr.Length;
// in case the rotating factor is
// greater than array length
d = d % n;
reverseArray(arr, 0, d - 1);
reverseArray(arr, d, n - 1);
reverseArray(arr, 0, n - 1);
}
/* Function to reverse arr[] from
index start to end*/
static void reverseArray( int [] arr, int start, int end)
{
int temp;
while (start <
end) {
temp = arr[start];
arr[start] = arr[end];
arr[end] = temp;
start++;
end--;
}
}
/*UTILITY FUNCTIONS*/
/* function to print an array */
static void printArray( int [] arr)
{
for ( int i = 0;
i <
arr.Length;
i++)
Console.Write(arr[i] + " " );
}
// Driver code
public static void Main()
{
int [] arr = { 1, 2, 3, 4, 5, 6, 7 };
int n = arr.Length;
int d = 2;
leftRotate(arr, d);
// Rotate array by 2
printArray(arr);
}
}
// This code is contributed by Sam007
的PHP
<
?php
// PHP program for reversal
// algorithm of array rotation
/* Function to left rotate
arr of size n by d */
function leftRotate(&
$arr , $d , $n )
{
if ( $d == 0)
return ;
// in case the rotating factor is
// greater than array length
$d = ( $d % $n );
reverseArray( $arr , 0, $d - 1);
reverseArray( $arr , $d , $n - 1);
reverseArray( $arr , 0, $n - 1);
}
/*Function to reverse $arr
from index start to end*/
function reverseArray(&
$arr , $start , $end )
{
while ( $start <
$end )
{
$temp = $arr [ $start ];
$arr [ $start ] = $arr [ $end ];
$arr [ $end ] = $temp ;
$start ++;
$end --;
}
}
// Function to
// print an array
function printArray( $arr , $size )
{
for ( $i = 0;
$i <
$size ;
$i ++)
print $arr [ $i ]. " " ;
}
// Driver code
$arr = array (1, 2, 3, 4, 5, 6, 7);
$n = sizeof( $arr );
$d = 2;
// Function calling
leftRotate( $arr , $d , $n );
printArray( $arr , $n );
// This code is contributed
// by ChitraNayal
?>
输出:
3 4 5 6 7 1 2
时间复杂度:
上)
【阵列旋转的逆向算法】如果发现任何不正确的地方, 或者想分享有关上述主题的更多信息, 请发表评论。
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