Android通知会多次打开，而不是只打开一次 _Android

【Android通知会多次打开，而不是只打开一次】少年击剑更吹箫，剑气箫心一例消。这篇文章主要讲述Android通知会多次打开，而不是只打开一次相关的知识，希望能为你提供帮助。
我正在尝试在将孩子添加到我的Firebase实时数据库时显示通知。仅当子项添加了与当前用户键匹配时，才能打开该通知。
它通常在添加子项时显示，但每次打开应用程序时（On Create方法），它都会一次又一次地显示。在某种程度上，这确实很好。但是，每当应用程序被杀或添加另一个孩子时，它都会显示，即使用户键不是当前用户。
此外，有时，当通知打开时，它会同时重复2或3次。
这是服务的代码

public class ListenTheOrderAgain extends Service {//Firebase FirebaseDatabase db; DatabaseReference orders; Query query; FirebaseAuth auth; FirebaseUser user; String currenNego; DatabaseReference socioReff; private String negocioOn, off; @Override public void onCreate() { super.onCreate(); auth = FirebaseAuth.getInstance(); user = auth.getCurrentUser(); if(user == null){} else {currenNego = auth.getCurrentUser().getUid(); socioReff = FirebaseDatabase.getInstance().getReference().child("Shippers").child(currenNego); }db = FirebaseDatabase.getInstance(); orders = db.getReference("Solicitudes"); }@Override public int onStartCommand(Intent intent, int flags, int startId) {if(user == null){} else {socioReff.addListenerForSingleValueEvent(new ValueEventListener() { @Override public void onDataChange(@NonNull DataSnapshot dataSnapshot) {if((dataSnapshot.exists()) & & (dataSnapshot.hasChild("is_working"))){query = orders.orderByChild("shipper").equalTo(currenNego); query.addChildEventListener(new ChildEventListener() { @Override public void onChildAdded(@NonNull DataSnapshot dataSnapshot, @Nullable String s) {//Trigger herePedidoModel result = dataSnapshot.getValue(PedidoModel.class); if (result.getShipper().equals(currenNego)) {showNotification8(dataSnapshot.getKey(), result); }}@Override public void onChildChanged(@NonNull DataSnapshot dataSnapshot, @Nullable String s) {}@Override public void onChildRemoved(@NonNull DataSnapshot dataSnapshot) {}@Override public void onChildMoved(@NonNull DataSnapshot dataSnapshot, @Nullable String s) {}@Override public void onCancelled(@NonNull DatabaseError databaseError) {} }); ///end} }@Override public void onCancelled(@NonNull DatabaseError databaseError) {} }); } return super.onStartCommand(intent, flags, startId); }public ListenTheOrderAgain() { }@Override public IBinder onBind(Intent intent) { // TODO: Return the communication channel to the service. throw new UnsupportedOperationException("Not yet implemented"); }public void showNotification8(String key, PedidoModel request) { NotificationManager notificationManager = (NotificationManager) getApplicationContext().getSystemService(Context.NOTIFICATION_SERVICE); Intent intent = new Intent(getApplicationContext(), MainActivity.class); PendingIntent contentIntent = PendingIntent.getActivity(getApplicationContext(), 0, intent , 0); int notificationId = 1; String channelId = "channel-01"; String channelName = "Channel Name"; int importance = NotificationManager.IMPORTANCE_HIGH; if (android.os.Build.VERSION.SDK_INT > = android.os.Build.VERSION_CODES.O) { NotificationChannel mChannel = new NotificationChannel( channelId, channelName, importance); notificationManager.createNotificationChannel(mChannel); NotificationCompat.Builder mBuilder = new NotificationCompat.Builder(getApplicationContext(), channelId) .setTicker("Test Order") .setContentInfo("New Order") .setContentText("Hello, you have a new Order #" + key) .setSmallIcon(R.mipmap.ic_launcher) .setContentIntent(contentIntent); TaskStackBuilder stackBuilder = TaskStackBuilder.create(getApplicationContext()); stackBuilder.addNextIntent(intent); PendingIntent resultPendingIntent = stackBuilder.getPendingIntent( 0, PendingIntent.FLAG_UPDATE_CURRENT ); mBuilder.setContentIntent(resultPendingIntent); notificationManager.notify(notificationId, mBuilder.build()); } else if(Build.VERSION.SDK_INT < Build.VERSION_CODES.O){Intent intents = new Intent(getApplicationContext(), MainActivity.class); PendingIntent contentIntents = PendingIntent.getActivity(getApplicationContext(), 0, intent , 0); NotificationCompat.Builder builders = new NotificationCompat.Builder(getApplicationContext()); builders.setAutoCancel(true).setDefaults(Notification.DEFAULT_ALL) .setTicker("Test Order") .setContentInfo("New Order") .setContentText("Hello you have a new ORder #" + key) .setSmallIcon(R.mipmap.ic_launcher) .setContentIntent(contentIntents) .setLights(Color.BLUE, 500, 500); NotificationManager managers = (NotificationManager)getApplicationContext().getSystemService(Context.NOTIFICATION_SERVICE); //IF YOU WANT TO MANY NOTFICATION SHOW, YOU NEED GIVE UNIQUE ID OFR ECHA NOTIFICAICIONint randomInt = new Random().nextInt(9999-1)+1; managers.notify(randomInt, builders.build()); } } }

这就是我从Main活动中调用服务的方式：

//Call service Intent service = new Intent(MainActivity.this, ListenTheOrderAgain.class); startService(service);

请帮我！
答案我认为最好创建一个FirebaseMessagingService：
在清单中：

< service android:name=".ListenTheOrderAgain" android:enabled="true" android:exported="true"> < intent-filter> < action android:name="com.google.firebase.MESSAGING_EVENT" /> < /intent-filter> < /service>

在您的服务中：

public class ListenTheOrderAgain extends FirebaseMessagingService {@Override public void onMessageReceived(RemoteMessage remoteMessage) { super.onMessageReceived(remoteMessage); //your code for reading notifications }

而且您不必调用startService。这项服务没有它。