#yyds干货盘点#剑指 Offer 10- I. 斐波那契数列

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我的答案

class Solution { public int fib(int n) { int x =f(n); return x%1000000007; }public int f(int n){ if(n< 0) return -1; if(n==0) return 0; if(n==1) return 1; else return f(n-1)+f(n-2); } }

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(°д°)
【#yyds干货盘点#剑指 Offer 10- I. 斐波那契数列】修改后

class Solution { int a=0,b=1; int res; public int fib(int n) {if(n< 0) return -1; else if(n==0) return 0; else if(n==1) return 1; else for(int i=1; i< n; i++){ res = a+b; a=b; b=res%1000000007; }return res%1000000007; } }

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优秀答案
O(1)复杂度

int f[]={0,1,1,2,3,5,8,13,21,34,55,89,144,233,377,610,987,1597,2584,4181,6765,10946,17711,28657,46368,75025,121393,196418,317811,514229,832040,1346269,2178309,3524578,5702887,9227465,14930352,24157817,39088169,63245986,102334155,165580141,267914296,433494437,701408733,134903163,836311896,971215059,807526948,778742000,586268941,365010934,951279875,316290802,267570670,583861472,851432142,435293607,286725742,722019349,8745084,730764433,739509517,470273943,209783453,680057396,889840849,569898238,459739080,29637311,489376391,519013702,8390086,527403788,535793874,63197655,598991529,662189184,261180706,923369890,184550589,107920472,292471061,400391533,692862594,93254120,786116714,879370834,665487541,544858368,210345902,755204270,965550172,720754435,686304600,407059028,93363621,500422649,593786270,94208912,687995182}; int fib(int n){ return f[n]; }