Python groupby方法删除所有连续的重复项 _python

给定字符串S, 删除所有连续的重复项。
例子：

Input: aaaaabbbbbb Output : abInput : srcmini Output : geksforgeksInput : aabccba Output : abcba

我们已经有解决此问题的方法, 请参阅从字符串中删除所有连续的重复项链接。我们可以使用python快速解决此问题itertools.groupby()方法。
itertools.groupby(iterable, key [optional])在Python中如何工作？
groupby方法需要两个输入, 一个是可迭代的(列表, 元组, 字典)第二个是密钥功能, 它为可迭代的每个元素计算密钥。它返回键和可迭代的分组项。如果未指定键函数或为” 无” , 则键默认为标识函数, 并返回不变的元素。例如,

numbers = [ 1 , 1 , 1 , 3 , 3 , 2 , 2 , 2 , 1 , 1 ] import itertools for (key, group) in itertools.groupby(numbers): print (key, list (group))

输出如下：

(1, [1, 1, 1]) (3, [3, 3]) (2, [2, 2]) (1, [1, 1])

# function to remove all consecutive duplicates # from the string in Pythonfrom itertools import groupby def removeAllConsecutive( input ):# group all consecutive characters based on their # order in string and we are only concerned # about first character of each consecutive substring # in given string, so key value will work for us # and we will join these keys without space to # generate resultant string result = [] for (key, group) in groupby( input ): result.append(key)print (''.join(result))# Driver program if __name__ = = "__main__" : input = 'aaaaabbbbbb' removeAllConsecutive( input )

参考文献：
https://docs.python.org/3/library/itertools.html
输出如下：