C++实现LeetCode(211.添加和查找单词-数据结构设计) C++实现LeetCode(211.添加和查找单

[LeetCode] 211.Add and Search Word - Data structure design 添加和查找单词-数据结构设计 Design a data structure that supports the following two operations:

void addWord(word)
bool search(word)

search(word) can search a literal word or a regular expression string containing only letters a-z or .. A . means it can represent any one letter.
For example:

addWord("bad")
addWord("dad")
addWord("mad")
search("pad") -> false
search("bad") -> true
search(".ad") -> true
search("b..") -> true

Note:
You may assume that all words are consist of lowercase letters a-z.
click to show hint.
You should be familiar with how a Trie works. If not, please work on this problem:Implement Trie (Prefix Tree) first. LeetCode出新题的速度越来越快了，有点跟不上节奏的感觉了。这道题如果做过之前的那道 Implement Trie (Prefix Tree) 实现字典树(前缀树)的话就没有太大的难度了，还是要用到字典树的结构，唯一不同的地方就是search的函数需要重新写一下，因为这道题里面'.'可以代替任意字符，所以一旦有了'.'，就需要查找所有的子树，只要有一个返回true，整个search函数就返回true，典型的DFS的问题，其他部分跟上一道实现字典树没有太大区别，代码如下：

class WordDictionary {public:struct TrieNode {public:TrieNode *child[26]; bool isWord; TrieNode() : isWord(false) {for (auto &a : child) a = NULL; }}; WordDictionary() {root = new TrieNode(); }// Adds a word into the data structure.void addWord(string word) {TrieNode *p = root; for (auto &a : word) {int i = a - 'a'; if (!p->child[i]) p->child[i] = new TrieNode(); p = p->child[i]; }p->isWord = true; }// Returns if the word is in the data structure. A word could// contain the dot character '.' to represent any one letter.bool search(string word) {return searchWord(word, root, 0); }bool searchWord(string &word, TrieNode *p, int i) {if (i == word.size()) return p->isWord; if (word[i] == '.') {for (auto &a : p->child) {if (a && searchWord(word, a, i + 1)) return true; }return false; } else {return p->child[word[i] - 'a'] && searchWord(word, p->child[word[i] - 'a'], i + 1); }}private:TrieNode *root; }; // Your WordDictionary object will be instantiated and called as such:// WordDictionary wordDictionary; // wordDictionary.addWord("word"); // wordDictionary.search("pattern");

讨论：这道题有个很好的Follow up，就是当搜索的单词中存在星号怎么搞，星号的定义和Wildcard Matching中一样，可以代表任意的字符串，包括空字符串，请参见评论区1楼。
【C++实现LeetCode(211.添加和查找单词-数据结构设计)】类似题目：
Implement Trie (Prefix Tree)
Wildcard Matching
参考资料：
https://leetcode.com/discuss/36246/my-java-trie-based-solution
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