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c语言代码，C语言求代码

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1，C语言求代码分析：f(n) = 1 (n =1 || n=2)f(n) = f(n-1) + f(n-2)代码如下：#include <stdio.h>int fun(int n)if(n == 1 || n == 2)return 1;}elsereturn (fun(n-1) + fun(n-2));}}void main()int n = 30;printf("when N=30== >fun = %d\n", fun(n));}【c语言代码，C语言求代码】
2，C语言求代码#include<stdio.h>void main() int n,a,b,c,d;; printf("输入金额："); scanf("%d",&n); a=n/20; b=(n%20)/10; c=(n%10)/5; d=(n%5)/1; printf("$20bills:%d\n$10bills:%d\n$5bills:%d\n$1bills:%d\n",a,b,c,d);}#include <stdio.h>int main() int amount,count,y; printf("Enter a dollar amount(整数):"); scanf("%d",&amount); for(int x=20;x>=5;x=x/2) count=0; count=amount/x; amount-=count*x; y+=count; printf("$%d bills:%d \n",x,count); } printf("$1 bills:%d \n",amount); return 0;}什么代码啊
3，C语言需要代码#include<stdio.h>int main() int i,j; for(i=1;i<=9;i++)printf("%*s",72-8*i,"");for(j=1;j<=i;j++)printf("%d*%d=%2d",j,i,j*i);printf("\n"); } return 0;}在下从事编程工作若干年了，如果说有什么捷径的话那就是多上机、多编译、多调试、多写代码、多总结 。光看代码没用，光学习也没用 ， 一定要注意多总结 。不用记代码，重要的是算法，是思想 。C语言程序：#include <stdio.h>void main()int i, j;for(i=1; i<=9; i++)//输出前导空格for(j=0; j<(9-i)*8; j++)printf(" ");}//输出乘式for(j=1; j<=i; j++)printf("%d*%d=%2d", j, i, i*j);}printf("\n");}}运行结果：
4，求C语言基础代码C菜鸟助手成员tonytvb为你解答（如有疑问请hi我或向我的团队提问）：#includeint main()int year,month;scanf("%d %d",&year,&month);if(month>12||monthprintf("year:%d,month:%d\n",year,month);if(month==1||month==3||month==5||month==7||month==8||month==10||month==12)printf("31 days\n");elseif(month==4||month==6||month==9||month==11)printf("30 days\n");elseif((month==2&&year%400==0)||(month==2&&year%4==0&&year%100!=0))printf("29 days\n");else printf("28 days\n");return 0;}#include #include int isLeepYear(int year) return (year%4==0&&year%100!=0||year%400==0);}int getDaysOfMonth(int year,int month) int nDays[13]= if(year12) return 0; nDay=nDays[month]; if(isLeepYear(year)&&month==2) nDay++; return nDay;}int main() int year,month; printf("请输入年份和月份:\n"); scanf("%d %d",&year,&month); printf("%d年%d月有%d天\n",year,month,getDaysOfMonth(year,month)); system("pause"); return 0;}

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