如何使用JavaScript检查元素是否是父元素的子元素（） _JavaScript

方法1：使用Node.contains()方法
Node.contains()方法用于检查给定节点是否是任何级别的另一个节点的后代。后代可以直接是子元素的父元素, 也可以是子元素的父元素。它返回结果的布尔值。
在父元素上使用此方法, 并且在该方法中传递的参数是要检查的子元素。如果子元素是父元素的后代, 则返回true。这意味着该元素是父级的子级。
语法如下：

function checkParent(parent, child) { if (parent.contains(child)) return true ; return false ; }

例子：

< html > < head > < title > How to Check if an element is a child of a parent using JavaScript? < / title > < style > .parent, .child, .non-child { border: 2px solid; padding: 5px; margin: 5px; } < / style > < / head > < body > < h1 style = "color: green" > lsbin< / h1 > < b > How to Check if an element is a child of a parent using JavaScript? < / b > < div class = "parent" > This is the parent div. < div class = "child" > This is the child div. < / div > < / div > < div class = "non-child" > This is outside the parent div. < / div > < p > Click on the button to check if the elements are child of a parent.< / p > < p > Child has parent: < span class = "output-child" > < / span > < / p > < p > Non-Child has parent: < span class = "output-non-child" > < / span > < / p > < button onclick = "checkElements()" > Check elements < / button > < script > function checkParent(parent, child) { if (parent.contains(child)) return true; return false; }function checkElements() { parent = document.querySelector('.parent'); child = document.querySelector('.child'); non_child = document.querySelector('.non-child'); output_child = checkParent(parent, child); output_non_child = checkParent(parent, non_child); document.querySelector('.output-child').textContent = output_child; document.querySelector('.output-non-child').textContent = output_non_child; } < / script > < / body > < / html >

输出如下：
在单击按钮之前：

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单击按钮后：

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方法2：遍历给定子元素的父元素
通过不断地逐个元素地循环访问元素的父元素, 可以检查子元素是否具有给定的父元素。通过访问以下节点找到每个节点的父节点parentNode返回父节点(如果有)的属性。
使用while循环, 直到找到所需的父级或不再存在任何父级元素为止。在此循环内, 每次迭代中都会找到每个元素的父节点。如果父节点在任何迭代中都与给定节点匹配, 则意味着该元素是父节点的子节点。
语法如下：

function checkParent(parent, child) { let node = child.parentNode; // keep iterating unless null while (node != null ) { if (node == parent) { return true ; } node = node.parentNode; } return false ; }

例子：

< html > < head > < title > How to Check if an element is a child of a parent using JavaScript? < / title > < style > .parent, .child, .non-child { border: 2px solid; padding: 5px; margin: 5px; } < / style > < / head > < body > < h1 style = "color: green" > lsbin< / h1 > < b > How to Check if an element is a child of a parent using JavaScript? < / b > < div class = "parent" > This is the parent div. < div class = "child" > This is the child div. < / div > < / div > < div class = "non-child" > This is outside the parent div. < / div > < p > Click on the button to check if the elements are child of a parent.< / p > < p > Child has parent: < span class = "output-child" > < / span > < / p > < p > Non-Child has parent: < span class = "output-non-child" > < / span > < / p > < button onclick = "checkElements()" > Check elements < / button > < script > function checkParent(parent, child) { let node = child.parentNode; // keep iterating unless null while (node != null) { if (node == parent) { return true; } node = node.parentNode; } return false; }function checkElements() { parent = document.querySelector('.parent'); child = document.querySelector('.child'); non_child = document.querySelector('.non-child'); output_child = checkParent(parent, child); output_non_child = checkParent(parent, non_child); document.querySelector('.output-child').textContent = output_child; document.querySelector('.output-non-child').textContent = output_non_child; } < / script > < / body > < / html >

输出如下：
在单击按钮之前：