760. Find Anagram Mappings 查找映射

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  Given two lists Aand B, and B is an anagram of A. B is an anagram of A means B is made by randomizing the order of the elements in A.
We want to find an index mapping P, from A to B. A mapping P[i] = j means the ith element in A appears in B at index j.
These lists A and B may contain duplicates.If there are multiple answers, output any of them.
For example, given

A = [12, 28, 46, 32, 50] B = [50, 12, 32, 46, 28]

We should return
[1, 4, 3, 2, 0]

as P[0] = 1 because the 0th element of A appears at B[1], and P[1] = 4 because the 1st element of A appears at B[4], and so on.
【760. Find Anagram Mappings 查找映射】Note:
  1. A, B have equal lengths in range [1, 100].
  2. A[i], B[i] are integers in range [0, 10^5].

给定两个A和B的列表,B是A的一个字母组。B是A的一个字母组,意味着B是通过随机化A中元素的顺序而制成的。
我们希望找到一个从A到B的索引映射P.映射P [i] = j意味着A中的第i个元素出现在索引为j的B中。
这些列表A和B可能包含重复项。如果有多个答案,则输出它们中的任何一个。

  1. /**
  2. * @param {number[]} A
  3. * @param {number[]} B
  4. * @return {number[]}
  5. */
  6. var anagramMappings = function (A, B) {
  7. let res = [];
  8. res.length = A.length;
  9. let m = {};
  10. for (let i = 0; i < B.length; i++) {
  11. m[B[i]] = i;
  12. }
  13. for (let i in A) {
  14. res[i] = m[A[i]];
  15. }
  16. return res;
  17. };
  18. let A = [12, 28, 46, 32, 50];
  19. let B = [50, 12, 32, 46, 28];
  20. let res = anagramMappings(A, B);
  21. console.log(res);





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