算法题（Hosoya三角形介绍和代码实现） _三角形

本文概述

C ++
Java
Python3
C#
的PHP
C ++
Java
Python3
C#
的PHP

斐波那契三角形或Hosoya三角形是基于斐波那契数的三角形排列。每个数字都是上面左对角线或右对角线上两个数字的和。前几行是:

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【算法题（Hosoya三角形介绍和代码实现）】这个三角形中的数字遵循递归关系

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与斐波那契数的关系
三角形中的条目满足标识

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因此，最外面的两条对角线是斐波那契数，而中间垂直线上的数字是斐波那契数的平方。三角形中所有其他的数都是两个不同的大于1的斐波那契数的乘积。行和是第一个卷积的斐波那契数。
stackoverflow：https://stackoverflow.com/questions/36275039/create-a-hosoyas-triangle-in-java
维基百科：https://en.wikipedia.org/wiki/Hosoya%27s_triangle
给定一个整数n，任务是打印Hosoya的大小为n的三角形。
例子：

Input : n = 4 Output : 1 1 1 2 1 2 3 2 2 3Input : n = 5 Output : 1 1 1 2 1 2 3 2 2 3 5 3 4 3 5

下面是打印Hosoya的高度为n的三角形的实现：
C ++

// CPP Program to print Hosoya's // triangle of height n. #include < bits/stdc++.h> using namespace std; int Hosoya( int n, int m) { // Base case if ((n == 0 & & m == 0) || (n == 1 & & m == 0) || (n == 1 & & m == 1) || (n == 2 & & m == 1)) return 1; // Recursive step if (n > m) return Hosoya(n - 1, m) + Hosoya(n - 2, m); else if (m == n) return Hosoya(n - 1, m - 1) + Hosoya(n - 2, m - 2); else return 0; }// Print the Hosoya triangle of height n. void printHosoya( int n) { for ( int i = 0; i < n; i++) { for ( int j = 0; j < = i; j++) cout < < Hosoya(i, j) < < " " ; cout < < endl; } }// Driven Program int main() { int n = 5; printHosoya(n); return 0; }

Java

// Java Program to print Hosoya's // triangle of height n. import java.util.*; class GFG {static int Hosoya( int n, int m) { // Base case if ((n == 0 & & m == 0 ) || (n == 1 & & m == 0 ) || (n == 1 & & m == 1 ) || (n == 2 & & m == 1 )) return 1 ; // Recursive step if (n > m) return Hosoya(n - 1 , m) + Hosoya(n - 2 , m); else if (m == n) return Hosoya(n - 1 , m - 1 ) + Hosoya(n - 2 , m - 2 ); else return 0 ; }// Print the Hosoya triangle of height n. static void printHosoya( int n) { for ( int i = 0 ; i < n; i++) { for ( int j = 0 ; j < = i; j++) System.out.print(Hosoya(i, j) + " " ); System.out.println( "" ); } }/* Driver program to test above function */ public static void main(String[] args) { int n = 5 ; printHosoya(n); } }// This code is contributed byArnav Kr. Mandal.

Python3

# Python3 code to print Hosoya's # triangle of height n.def Hosoya( n , m ):# Base case if ((n = = 0 and m = = 0 ) or (n = = 1 and m = = 0 ) or (n = = 1 and m = = 1 ) or (n = = 2 and m = = 1 )): return 1# Recursive step if n > m: return Hosoya(n - 1 , m) + Hosoya(n - 2 , m)elif m = = n: return Hosoya(n - 1 , m - 1 ) + Hosoya(n - 2 , m - 2 )else : return 0# Print the Hosoya triangle of height n. def printHosoya( n ): for i in range (n): for j in range (i + 1 ): print (Hosoya(i, j) , end = " " ) print ( "\n" , end = "")# Driven Code n = 5 printHosoya(n)# This code is contributed by Sharad_Bhardwaj

// C# Program to print Hosoya's // triangle of height n. using System; class GFG {static int Hosoya( int n, int m) { // Base case if ((n == 0 & & m == 0) || (n == 1 & & m == 0) || (n == 1 & & m == 1) || (n == 2 & & m == 1)) return 1; // Recursive step if (n > m) return Hosoya(n - 1, m) + Hosoya(n - 2, m); else if (m == n) return Hosoya(n - 1, m - 1) + Hosoya(n - 2, m - 2); else return 0; }// Print the Hosoya triangle of height n. static void printHosoya( int n) { for ( int i = 0; i < n; i++) { for ( int j = 0; j < = i; j++) Console.Write(Hosoya(i, j) + " " ); Console.WriteLine( "" ); } }/* Driver program to test above function */ public static void Main() { int n = 5; printHosoya(n); } }// This code is contributed by vt_m.

的PHP

< ?php // PHP Program to print Hosoya's // triangle of height n.function Hosoya(int $n , int $m ) { // Base case if (( $n == 0 & & $m == 0) || ( $n == 1 & & $m == 0) || ( $n == 1 & & $m == 1) || ( $n == 2 & & $m == 1)) return 1; // Recursive step if ( $n > $m ) return Hosoya( $n - 1, $m ) + Hosoya( $n - 2, $m ); else if ( $m == $n ) return Hosoya( $n - 1, $m - 1) + Hosoya( $n - 2, $m - 2); else return 0; }// Print the Hosoya // triangle of height n. function printHosoya( $n ) { for ( $i = 0; $i < $n ; $i ++) { for ( $j = 0; $j < = $i ; $j ++) echo Hosoya( $i , $j ) , " " ; echo "\n" ; } }// Driven Code $n = 5; printHosoya( $n ); // This code is contributed by anuj_67. ?>

输出：

1 1 1 2 1 2 3 2 2 3 5 3 4 3 5

下面是使用动态编程打印高度为n的Hosoya三角形的实现：
C ++

// CPP Program to print Hosoya's triangle of height n. #include < bits/stdc++.h> #define N 5 using namespace std; // Print the Hosoya triangle of height n. void printHosoya( int n) { int dp[N][N]; memset (dp, 0, sizeof (dp)); // base case. dp[0][0] = dp[1][0] = dp[1][1] = 1; // For each row. for ( int i = 2; i < n; i++) {// for each column; for ( int j = 0; j < n; j++) {// recursive steps. if (i > j) dp[i][j] = dp[i - 1][j] + dp[i - 2][j]; else dp[i][j] = dp[i - 1][j - 1] + dp[i - 2][j - 2]; } }// printing the solution for ( int i = 0; i < n; i++) { for ( int j = 0; j < = i; j++) cout < < dp[i][j] < < " " ; cout < < endl; } }// Driven Program int main() { int n = 5; printHosoya(n); return 0; }

Java

// JAVA Code for Hosoya Triangle import java.util.*; class GFG {static int N = 5 ; // Print the Hosoya triangle // of height n. static void printHosoya( int n) { int dp[][] = new int [N][N]; // base case. dp[ 0 ][ 0 ] = dp[ 1 ][ 0 ] = 1 ; dp[ 1 ][ 1 ] = 1 ; // For each row. for ( int i = 2 ; i < n; i++) { // for each column; for ( int j = 0 ; j < n; j++) { // recursive steps. if (i > j) dp[i][j] = dp[i - 1 ][j] + dp[i - 2 ][j]; else dp[i][j] = dp[i - 1 ][j - 1 ] + dp[i - 2 ][j - 2 ]; } }// printing the solution for ( int i = 0 ; i < n; i++) { for ( int j = 0 ; j < = i; j++) System.out.print(dp[i][j] + " " ); System.out.println( "" ); } }/* Driver program*/ public static void main(String[] args) { int n = 5 ; printHosoya(n); } }// This code is contributed by Arnav Kr. Mandal.

Python3

# Python3 Program to print # Hosoya's triangle of height n. N = 5# Print the Hosoya triangle # of height n. def printHosoya(n): dp = [[ 0 for i in range (N)] for i in range (N)]# base case. dp[ 0 ][ 0 ] = dp[ 1 ][ 0 ] = dp[ 1 ][ 1 ] = 1# For each row. for i in range ( 2 , n):# for each column for j in range (n):# recursive steps. if (i > j): dp[i][j] = (dp[i - 1 ][j] + dp[i - 2 ][j]) else : dp[i][j] = (dp[i - 1 ][j - 1 ] + dp[i - 2 ][j - 2 ])# printing the solution for i in range (n): for j in range (i + 1 ): print (dp[i][j], end = ' ' ) print ()# Driver Code n = 5 printHosoya(n)# This code is contributed # by sahilshelangia

// C# Code for Hosoya Triangle using System; class GFG {static int N = 5; // Print the Hosoya triangle // of height n. static void printHosoya( int n) { int [, ]dp = new int [N, N]; // base case. dp[0, 0] = dp[1, 0] = 1; dp[1, 1] = 1; // For each row. for ( int i = 2; i < n; i++) { // for each column; for ( int j = 0; j < n; j++) { // recursive steps. if (i > j) dp[i, j] = dp[i - 1, j] + dp[i - 2, j]; else dp[i, j] = dp[i - 1, j - 1] + dp[i - 2, j - 2]; } }// printing the solution for ( int i = 0; i < n; i++) { for ( int j = 0; j < = i; j++) Console.Write(dp[i, j] + " " ); Console.WriteLine( "" ); } }/* Driver program*/ public static void Main() { int n = 5; printHosoya(n); } }// This code is contributed by Vt_m.

的PHP

< ?php // PHP Program to print Hosoya's triangle of height n. $N =5; // Print the Hosoya triangle of height n. function printHosoya( $n ) { global $N ; $dp = array_fill (0, $N , array_fill (0, $N , 0)); // base case. $dp [0][0] = $dp [1][0] = $dp [1][1] = 1; // For each row. for ( $i = 2; $i < $n ; $i ++) {// for each column; for ( $j = 0; $j < $n ; $j ++) {// recursive steps. if ( $i > $j ) $dp [ $i ][ $j ] = $dp [ $i - 1][ $j ] + $dp [ $i - 2][ $j ]; else $dp [ $i ][ $j ] = $dp [ $i - 1][ $j - 1] + $dp [ $i - 2][ $j - 2]; } }// printing the solution for ( $i = 0; $i < $n ; $i ++) { for ( $j = 0; $j < = $i ; $j ++) echo $dp [ $i ][ $j ]. " " ; echo "\n" ; } }// Driven Program$n = 5; printHosoya( $n ); // This code is contributed by mits ?>

输出：