旋转字符串

【旋转字符串】LintCode题目地址

def rotateString(self, str, offset): # write your code here n = len(str)if offset < 0 or n == 0: return str offset = offset % ni, j = 0, len(str) - 1temp = (str + str)[n - offset : 2 * n - offset]for i in xrange(len(temp)): str[i] = temp[i]

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