[Leetcode]|[Leetcode] 87. Binary Tree Level Order Traversal II

题目
Given a binary tree, return the bottom-up level order traversal of its nodes' values. (ie, from left to right, level by level from leaf to root).
For example:
Given binary tree {3,9,20,#,#,15,7},

3 / \ 920 /\ 157

return its bottom-up level order traversal as:
【[Leetcode]|[Leetcode] 87. Binary Tree Level Order Traversal II】[
[15,7],
[9,20],
[3]
]
解题之法
/** * Definition for a binary tree node. * struct TreeNode { *int val; *TreeNode *left; *TreeNode *right; *TreeNode(int x) : val(x), left(NULL), right(NULL) {} * }; */ class Solution { public: vector> levelOrderBottom(TreeNode* root) { vector > res; levelorder(root, 0, res); return vector > (res.rbegin(), res.rend()); } void levelorder(TreeNode *root, int level, vector > &res) { if (!root) return; if (res.size() == level) res.push_back({}); res[level].push_back(root->val); if (root->left) levelorder(root->left, level + 1, res); if (root->right) levelorder(root->right, level + 1, res); } };

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