每日一题|牛客网HJ21 简单密码每日一题|c语言

牛客网 HJ21 简单密码

#include int main() { char arr[101] = { 0 }; int ch = 0; int j = 0; while ((ch = getchar()) != '\n') { if (ch >= 'A' && ch <= 'Z') { if (ch == 'Z') { ch = 'a'; } else { ch = ch + 'a' - 'A' + 1; }} else if (ch >= 'a' && ch <= 'z') { switch (ch) { case 'a': case 'b': case 'c': ch = '2'; break; case 'd': case 'e': case 'f': ch = '3'; break; case 'g': case 'h': case 'i': ch = '4'; break; case 'j': case 'k': case 'l': ch = '5'; break; case 'm': case 'o': case 'n': ch = '6'; break; case 'p': case 'q': case 'r': case 's': ch = '7'; break; case 't': case 'u': case 'v': ch = '8'; break; case 'w': case 'x': case 'y': case 'z': ch = '9'; break; } } arr[j++] = ch; } printf("%s\n", arr); return 0; }

【每日一题|牛客网HJ21 简单密码】