【leetcode刷题:The string "PAYPALISHIRING"】题目描述：The string “PAYPALISHIRING” is written in a zigzag pattern on a given number of rows like this: (you may want to display this pattern in a fixed font for better legibility)
P…….A……..H…….N
..A..P….L..S….I…I….G
….Y………I……..R
And then read line by line: “PAHNAPLSIIGYIR”
Write the code that will take a string and make this conversion given a number of rows:
string convert(string text, int nRows);
convert(“PAYPALISHIRING”, 3) should return “PAHNAPLSIIGYIR”.
Therefore, s = ABCD, row = 2， can be arranged as:
A….C
…B….D
由于原题对于题目描述不太清楚，我照着disscuss里面加了一个例子描述，方便阅读。
首先是我自己的代码：
/****************************************/
string s = “ABC”;
int numRows = 2 ;
if (s.size() == 1)
{
cout << s.size();
return 0;
}
string str;
int num2 = numRows / 2;
char ch[1000][1000];
int row = 0;
int i = 0;
for (int i = 0;
i < 200;
i++)
{
for (int j = 0;
j < 200;
j++)
{
ch[i][j] = ’ ‘;
}
}
while (i < s.size())
{
for (int j = 0;
j < numRows;
j++, row++) {
ch[j][row] = s[i];
i++;
}
}
i = 0;
while (i菜鸡继续加油。。。
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