1.学习内容 本节我们将学习OpenCV的pointPolygonTest()函数:
C++:
double cv::pointPolygonTest (InputArray contour, Point2f pt, bool measureDist)
Python:
cv.pointPolygonTest(contour, pt, measureDist) ->retval
参数:
contour:输入轮廓。
pt:要测试的点。
measureDist:如果为真,该函数估计从点到最近的轮廓边缘的符号距离。否则,函数只检查点是否在轮廓线内。
该函数确定点是在轮廓线内、外,还是位于边缘(或与顶点重合)。它会相应地返回正(内部)、负(外部)或零(边缘)值。当measureDist=false时,返回值分别是**+1**,-1和0。否则,返回值是点和最近的轮廓边缘之间的带符号距离。
2.代码案例 2.1 Python代码
from __future__ import print_function
from __future__ import division
import cv2 as cv
import numpy as np
# Create an image
r = 100
src = https://www.it610.com/article/np.zeros((4*r, 4*r), dtype=np.uint8)
# 创建六边形的6个顶点
vert = [None]*6
vert[0] = (3*r//2, int(1.34*r))
vert[1] = (1*r, 2*r)
vert[2] = (3*r//2, int(2.866*r))
vert[3] = (5*r//2, int(2.866*r))
vert[4] = (3*r, 2*r)
vert[5] = (5*r//2, int(1.34*r))
# 根据六个顶点画6边形
for i in range(6):
cv.line(src, vert[i],vert[(i+1)%6], ( 255 ), 3)
# 获取六边形的轮廓
contours, _ = cv.findContours(src, cv.RETR_TREE, cv.CHAIN_APPROX_SIMPLE)
# 计算图上点到六边形的距离(带符号)
raw_dist = np.empty(src.shape, dtype=np.float32)
for i in range(src.shape[0]):
for j in range(src.shape[1]):
raw_dist[i,j] = cv.pointPolygonTest(contours[0], (j,i), True)
# 查找带符号的最大最小值
minVal, maxVal, _, maxDistPt = cv.minMaxLoc(raw_dist)
minVal = abs(minVal)
maxVal = abs(maxVal)
# 用图形表示距离
drawing = np.zeros((src.shape[0], src.shape[1], 3), dtype=np.uint8)
for i in range(src.shape[0]):
for j in range(src.shape[1]):
if raw_dist[i,j] < 0:
drawing[i,j,0] = 255 - abs(raw_dist[i,j]) * 255 / minVal
elif raw_dist[i,j]> 0:
drawing[i,j,2] = 255 - raw_dist[i,j] * 255 / maxVal
else:
drawing[i,j,0] = 255
drawing[i,j,1] = 255
drawing[i,j,2] = 255
cv.circle(drawing,maxDistPt, int(maxVal),(255,255,255), 1, cv.LINE_8, 0)
cv.imshow('Source', src)
cv.imshow('Distance and inscribed circle', drawing)
cv.waitKey()
2.2 C++代码
#include
#include
#include
using namespace cv;
using namespace std;
int main( void )
{
const int r = 100;
Mat src = https://www.it610.com/article/Mat::zeros( Size( 4*r, 4*r ), CV_8U );
vector vert(6);
vert[0] = Point( 3*r/2, static_cast(1.34*r) );
vert[1] = Point( 1*r, 2*r );
vert[2] = Point( 3*r/2, static_cast(2.866*r) );
vert[3] = Point( 5*r/2, static_cast(2.866*r) );
vert[4] = Point( 3*r, 2*r );
vert[5] = Point( 5*r/2, static_cast(1.34*r) );
for( int i = 0;
i < 6;
i++ )
{
line( src, vert[i],vert[(i+1)%6], Scalar( 255 ), 3 );
}
vector contours;
findContours( src, contours, RETR_TREE, CHAIN_APPROX_SIMPLE);
Mat raw_dist( src.size(), CV_32F );
for( int i = 0;
i < src.rows;
i++ )
{
for( int j = 0;
j < src.cols;
j++ )
{
raw_dist.at(i,j) = (float)pointPolygonTest( contours[0], Point2f((float)j, (float)i), true );
}
}
double minVal, maxVal;
Point maxDistPt;
// inscribed circle center
minMaxLoc(raw_dist, &minVal, &maxVal, NULL, &maxDistPt);
minVal = abs(minVal);
maxVal = abs(maxVal);
Mat drawing = Mat::zeros( src.size(), CV_8UC3 );
for( int i = 0;
i < src.rows;
i++ )
{
for( int j = 0;
j < src.cols;
j++ )
{
if( raw_dist.at(i,j) < 0 )
{
drawing.at(i,j)[0] = (uchar)(255 - abs(raw_dist.at(i,j)) * 255 / minVal);
}
else if( raw_dist.at(i,j) > 0 )
{
drawing.at(i,j)[2] = (uchar)(255 - raw_dist.at(i,j) * 255 / maxVal);
}
else
{
drawing.at(i,j)[0] = 255;
drawing.at(i,j)[1] = 255;
drawing.at(i,j)[2] = 255;
}
}
}
circle(drawing, maxDistPt, (int)maxVal, Scalar(255,255,255));
imshow( "Source", src );
imshow( "Distance and inscribed circle", drawing );
waitKey();
return 0;
}
文章图片
参考目录 【OpenCV|多边形点测试】https://docs.opencv.org/4.x/dc/d48/tutorial_point_polygon_test.html
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